Primary : 4
Secondary : 3/0
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To answer this question correctly a voltage must be stated.
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For single phase, KVA = (line to ground) * (phase current). A 75kVA 480 to 208Y/120 volt transformer is a fairly common transformer. I assume this is the type of transformer you are referring to. 75k / 120 = 625 Amps. As an FYI, the 208Y voltage is the line to line voltage, which is equal to (phase 1) - (phase 2), where the phases are separated by 120 degrees, thus (phase 1) * 1.732 For three phase, kVA = (line to line voltage) * (phase current) *(sqrt 3), 75k / 208 / 1.732 = 208 Amps.
To wire a 15 kW dry type transformer for a 240V to 480V configuration, first ensure that the transformer is rated for this voltage conversion. Connect the primary side to the 240V supply by connecting each of the two primary terminals to the respective phases of the 240V supply. For the secondary side, connect the output terminals to the load requiring 480V, ensuring that the load is compatible with the transformer rating. Always follow local electrical codes and safety standards, and consider consulting a licensed electrician for installation.
To start a 15 hp motor, you typically need a transformer that can handle the motor's starting current, which can be significantly higher than its running current. Generally, the starting current can be 6 to 8 times the full-load current of the motor. For a 15 hp motor, the full-load current is about 18-20 amps at 230V or 10-12 amps at 460V, so the transformer should be rated to handle at least 100-160 amps. Additionally, it's advisable to consult the motor's specifications and consider factors like starting method and application to determine the exact transformer size.
15/600 * 200
The power in a 15 MVA (15000 KVA) transformer depends on the power factor. You did not specify the power factor, so I will assume a power factor of 0.92. Simply multiply MVA by PF and you get 13.8 MW.
To calculate the number of lights that can be run on the transformer, use the formula: Power (kVA) = Voltage (V) x Current (A) x √2 x Number of Phases. Rearranging the formula: Number of lights = (Power (kVA) / (Voltage (V) x Current (A) x √2). Plugging in the values: 15 kVA / (240 V x 4.9 A x √2) ≈ 6 lights.
The breaker size for a 10 KVA electric heater would depend on the voltage it operates at. For example, for a 240V heater, you would need a 41.67 Amp breaker (10,000 VA / 240V = 41.67 A). It is important to consult with a licensed electrician to ensure the correct breaker size and electrical setup for your specific heater.
Each phase supplies 15 kVA. The primary has a line-to-neutral voltage of 277 v so the line current is 15,000 / 277 or 54 amps. The secondary has a line-to-neutral voltage of 120v so the current is 15,000/120 or 125 amps.
AWG 10.
15 amps.
The minimum size home wiring is #14 AWG, the rating for that size wire is 15 amps.
For a 15 amp circuit, a 14-gauge wire should be used.
The minimum size home wiring is #14 AWG, the rating for that size wire is 15 amps.
The wire size depends on how much current it will conduct.
A 14 gauge wire is typically used on a 15 amp circuit breaker. It is not recommended to use a larger circuit breaker with a smaller wire size as this can create a fire hazard.
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