write an assembly language program to implement a stack. START: LXI SP,STACK ;initialize stack pointer
LXI H,BINBYT ;point HL index to where binary number is stored
MOV A,M ;transfer byte
LXI H,OUTBUF ;point HL index to output-buffer memory
CALL BINBCD
HLT BINBCD:
MVI B,100 ;load 100 into register B (power of ten holding register)
CALL BCD ;call conversion for BCD3
MVI B,10 ;load 10 into register B
CALL BCD ;call conversion for BCD2
MOV M,A ;store BCD1
RET
Chat with our AI personalities
Assume read from Console
string inputString = Console.ReadLine();
int inputDecimalValue = int.Parse(inputString);
//Now convert the input decimal value to a binary representation, as a string
string binaryString = Convert.ToString(inputDecimalValue, 2); // 2 means binary base
Use manipulator for cout stream dec which automatically converts to decimal representation.
...
#include
...
int main()
{
...
cout << ... << dec << ...;
...
}
write an algoriths/program that accepts an input as a decimal number and converts it into binary representation in c.
This is not a question.
write a c++ program to convert binary number to decimal number by using while statement
The hexadecimal notation is base-16, so for small numbers, arrange them right to left as powers of 16 (units 0 to 9 and A through F representing 10, 11, 12, 13, 14, and 15).Examples: 21 = 15 hex (16+5) and 31 = 1F (16+15)For larger numbers, see the process at the related link below.Here is a program:#include#includevoid main(){int n;clrscr();printf("Enter Decimal Number: ");scanf("%d",&n);printf("Hexadecimal value is: %x",n);getch();}
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
The question asks to do nothing by converting a decimal into itself. Perhaps the question was mistyped. Please restate the question.