write an assembly language program to implement a stack. START: LXI SP,STACK ;initialize stack pointer
LXI H,BINBYT ;point HL index to where binary number is stored
MOV A,M ;transfer byte
LXI H,OUTBUF ;point HL index to output-buffer memory
CALL BINBCD
HLT BINBCD:
MVI B,100 ;load 100 into register B (power of ten holding register)
CALL BCD ;call conversion for BCD3
MVI B,10 ;load 10 into register B
CALL BCD ;call conversion for BCD2
MOV M,A ;store BCD1
RET
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write a c++ program to convert binary number to decimal number by using while statement
The hexadecimal notation is base-16, so for small numbers, arrange them right to left as powers of 16 (units 0 to 9 and A through F representing 10, 11, 12, 13, 14, and 15).Examples: 21 = 15 hex (16+5) and 31 = 1F (16+15)For larger numbers, see the process at the related link below.Here is a program:#include#includevoid main(){int n;clrscr();printf("Enter Decimal Number: ");scanf("%d",&n);printf("Hexadecimal value is: %x",n);getch();}
import java.util.Scanner; public class NumberSystem { public void displayConversion() { Scanner input = new Scanner(System.in); System.out.printf("%-20s%-20s%-20s%-20s\n", "Decimal", "Binary", "Octal", "Hexadecimal"); for ( int i = 1; i <= 256; i++ ) { String binary = Integer.toBinaryString(i); String octal = Integer.toOctalString(i); String hexadecimal = Integer.toHexString(i); System.out.format("%-20d%-20s%-20s%-20s\n", i, binary, octal, hexadecimal); } } // returns a string representation of the decimal number in binary public String toBinaryString( int dec ) { String binary = " "; while (dec >= 1 ) { int value = dec % 2; binary = value + binary; dec /= 2; } return binary; } //returns a string representation of the number in octal public String toOctalString( int dec ) { String octal = " "; while ( dec >= 1 ) { int value = dec % 8; octal = value + octal; dec /= 8; } return octal; } public String toHexString( int dec ) { String hexadecimal = " "; while ( dec >= 1 ) { int value = dec % 16; switch (value) { case 10: hexadecimal = "A" + hexadecimal; break; case 11: hexadecimal = "B" + hexadecimal; break; case 12: hexadecimal = "C" + hexadecimal; break; case 13: hexadecimal = "D" + hexadecimal; break; case 14: hexadecimal = "E" + hexadecimal; break; case 15: hexadecimal = "F" + hexadecimal; break; default: hexadecimal = value + hexadecimal; break; } dec /= 16; } return hexadecimal; } public static void main( String args[]) { NumberSystem apps = new NumberSystem(); apps.displayConversion(); } }
The question asks to do nothing by converting a decimal into itself. Perhaps the question was mistyped. Please restate the question.
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Write a program to convert a 2-digit BCD number into hexadecimal
WRITE A PROGRAM TO CONVERT A 2-DIGIT bcd NUMBER INTO HEXADECIMAL
Write a program to convert a 2-digit BCD number into hexadecimal
hexadecimal dumper, which prints or displays the binary numbers of a program in hexadecimal format.
In order to convert binary to hexadecimal using assembly language, the programmer must possess an understanding on boolean algebra or binary system in other words. A compiler is also needed to complete the program.
write a c++ program to convert binary number to decimal number by using while statement
jump,b
Computer engineers use to use the hexadecimal code to program computers, or the base 16. Hexadecimal numbers use the digits 0 through 9, plus the letters A through F to represent the digits 10 through 15.
One way to accomplish this is to allow the printf statement to do the work for you. Example: printf("Decimal %d = hex %02x\n", number, number); Or you could use the windows calculator. Select the Dec radian, type your number in, then select Hex radian.
The hexadecimal notation is base-16, so for small numbers, arrange them right to left as powers of 16 (units 0 to 9 and A through F representing 10, 11, 12, 13, 14, and 15).Examples: 21 = 15 hex (16+5) and 31 = 1F (16+15)For larger numbers, see the process at the related link below.Here is a program:#include#includevoid main(){int n;clrscr();printf("Enter Decimal Number: ");scanf("%d",&n);printf("Hexadecimal value is: %x",n);getch();}