Write a program to find the sum of squares of n natural numbers using c plus plus?

Answer 1

#include
#include
void main()
{
int sum_sqr(int n);
clrscr();
printf("%d",sum_sqr(5));//Sum of first 5 natural numbers' square values
getch();
}
int sum_sqr(int n)
{
int i,sum=0;
for(i=1;i<=n;i++)
{
sum=sum+(i*i);
}
return sum;
}

output:
55

Answer 2

#include<iostream>

#include<random>

#include<time.h>

int main()

{

// pseudo-random number generator (range: 10 to 20, inclusive)

std::default_random_engine generator;

generator.seed ((unsigned) time (NULL));

std::uniform_int_distribution<unsigned> distribution (10, 20);

unsigned sum = 0;

unsigned n = distribution (generator);

for (unsigned i=0; i<n; ++i)

{

unsigned num = distribution (generator);

unsigned sqr = num * num;

std::cout << num << " squared is " << sqr << std::endl;

sum += sqr;

}

std::cout << "Sum of squares is " << sum << std::endl;

}

Answer 3

#include<stdio.h>

main()

{

int i,n,sum = 0;

printf("Program to find sum of n natural number\n");

printf("Enter the value of n ");

scanf("%d",&n);

for (i = 0;i <= n;i++)

{

sum = sum + i * i;

}

printf("The sum is %d",sum);

}

Answer 4

size_t sum_of_squares(size_t n)

{

size_t sum {0};

while (n)

{

sum += (n*n);

--n;

}

return sum;

}