Write a shell program to check odd or even number?

Answer 1

/*Programming in C...*/

#include


int main(void)
{

int n ;
printf("enter a number :");
scanf("%d",&n);

if(n%2==0)
{
printf("no is even\n");
}
else
printf("no. is odd\n");

return 0;
}

Answer 2

echo -n "Enter numnber : " read n rem=$(( $n % 2 )) if [ $rem -eq 0 ] then echo "$n is even number" else echo "$n is odd number" fi