Oh, what a lovely problem to solve! Let's paint a happy little picture here. If we let the length of the first piece be x meters, the second piece would be 3x meters long, and the third piece would be 4 times that, which is 12x meters. Together, they add up to 64 meters, so we can set up the equation x + 3x + 12x = 64 to find the lengths of each piece.
28=A+B+c b=2A c=4A subst. a=4 b=8 c=16
It depends on two things. First, one length, by itself, does not define a triangle. And second, it depends on what the question about the triangle is!
There is 90 feet between each base. So running from 1st to 3rd would equal 180 feet (90 to second, then 90 to third).
Yes, your statement is dimensionally correct. But your formula is incorrect, and possibly ambiguous. First, the perimeter is only a simple sum involving length and width IF the figure is a rectangle. Second, the perimeter of the rectangle is double what you have stated: P = 2L + 2W
The first and second coordinate. X is the first coordinate and y is the second.
You first need to find out what the pieces are. 12 mm is a measure of length. Length, by itself cannot be converted to an equivalent mass.
28=A+B+c b=2A c=4A subst. a=4 b=8 c=16
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)
3x + 12 + x = 21
No. The first, second and fifth lines are of similar length whilst the third and fourth are of a similar, shorter length.
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)
To find out how many pieces of ribbon each 4.5 cm long can be cut from a length of 4.5 metres, first convert 4.5 metres to centimetres: 4.5 metres is 450 cm. Next, divide the total length by the length of each piece: 450 cm ÷ 4.5 cm = 100. Therefore, you can cut 100 pieces of ribbon from a length of 4.5 metres.
I think 9 and 3... no, its 5 and 7.
2nd because you have some pieces on the board to work with.
20 inches
You divide the length of a side of the first figure by the length of the line in the same relative position in the second figure.
The first piece of paper in in the counterfeit banquet, the second is in the tour tunnel, find the rest