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Assume the first piece to be x met. Then the second = 3x and the third =12x . Together, x + 3x + 12x = 64 or 16x = 64 or x= 4 met. The three pieces, therefore, are 4m, 12m and 48 m

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Q: A 64m long rope is cut into 3 pieces The second piece is 3 times as long as the first pieceThe third piece is 4 times as long as the second piece What is the length of each piece?
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28=A+B+c b=2A c=4A subst. a=4 b=8 c=16


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Related questions

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