Assume the first piece to be x met. Then the second = 3x and the third =12x . Together, x + 3x + 12x = 64 or 16x = 64 or x= 4 met. The three pieces, therefore, are 4m, 12m and 48 m
28=A+B+c b=2A c=4A subst. a=4 b=8 c=16
It depends on two things. First, one length, by itself, does not define a triangle. And second, it depends on what the question about the triangle is!
First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.
There is 90 feet between each base. So running from 1st to 3rd would equal 180 feet (90 to second, then 90 to third).
Yes, your statement is dimensionally correct. But your formula is incorrect, and possibly ambiguous. First, the perimeter is only a simple sum involving length and width IF the figure is a rectangle. Second, the perimeter of the rectangle is double what you have stated: P = 2L + 2W
You first need to find out what the pieces are. 12 mm is a measure of length. Length, by itself cannot be converted to an equivalent mass.
28=A+B+c b=2A c=4A subst. a=4 b=8 c=16
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)
3x + 12 + x = 21
Perimeter of a triangle = (length of the first side) plus (length of the second side) plus (length of the third side)
No. The first, second and fifth lines are of similar length whilst the third and fourth are of a similar, shorter length.
I think 9 and 3... no, its 5 and 7.
2nd because you have some pieces on the board to work with.
the same
The third (3rd) dimension is depth. The first is length, the second is height
With a fork of known frequency, the first resonating length is found. Then by lowering down the level of water in the resonance column tube the second resonating length is found. This secondlength will be approximately three times the first resonating length Now using the following formula one can calcualte the speed of sound. Speed of sound = 2 x frequency x (Second length - first length)
When two similar shapes have a scale factor of 0.8, every length of the second is 0.8 times the corresponding length of the first.