The statue would be eight meters tall.
Set up the ratio 40/x = 30/6
Multiple both sides by 6x to get 40*6 = 30x or 240 = 30x
Divide both sides by 30 to get 8=x.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
If you mean the height of the building then it works out as 466.5063509 feet
It is 90 feet in height
From the given information, we see that the building and its shadow form a right triangle with base 30 ft and height 55 ft.Also, the person and his/her shadow form another similar triangle with base 3 ft and height x ft.Since both triangles are similar, we have:x/55 = 3/30 orx/55 = 1/10 cross multiply10x = 55 divide by 10 to both sidesx = 5.5Thus the person is 5.5 inches tall.
That depends on the height of the yardstick whose height has not been given.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Height of building/105 = 6/14 Multiply both sides by 105: Height = 630/14 Height = 45 feet
That varies depending on the height of the sun, whether the shadow is cast on a sloping surface and so forth.
If you mean the height of the building then it works out as 466.5063509 feet
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
(35/7)*4 = 20 Ft.
4 is to 6 as 5 is to X. 4/6 = 5/X. X = 7.5 feet.
2
Let x = the height of the building. So we have, x/2.6 = 42.25/1.51 x = (2.6)(42.25)/1.51 x =72.75 Thus, the building is 72.75 meter tall.
If the building casts a shadow, then the sun is out, and any man who is not standing in theshadow of the building will cast a shadow of his own, no matter how short or tall he may be.(If you had told us the length of the man's shadow, it would have been a completely differentquestion, and we could have had a completely different answer to offer in response.)
Let the height of the building be x and use the tangent ratio: x/20 = 6/4 Make x the subject of the equation: x = (6*20)/4 x = 30 ft
The height of the tree is in direct proportion to the pole and its shadow