If you mean the height of the building then it works out as 466.5063509 feet
Angle of elevation = 300/50 = 6 tan-1(6) = 80.53767779 degrees or 800 32' 15.64''
51
That depends on the angle of elevation which has not been given.
If the angle of elevation is 60 degrees then by using the tangent ratio the length of the shadow is 8.66 feet rounded to two decimal places.
Your missing the angle of elevation or depression.
Using trigonometry the angle of elevation is 77 degrees rounded to the nearest degree
36 degrees
Suppose the length of the shadow is s metres. Then tan(62 deg) = 45/S so that S = 45/tan(62 deg) = 45/1.88 (approx = 23.93 metres, approx.
If you also know its shadow then you can work out the angle of elevation
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
yes
The language of the question is too ambiguous. In mathematics, we use precise language to avoid this problem. point a is 40 metres from the base of building B the angle of elevation to the top of building C is 51 degree and to the top of the flagpole D on top of building is 56 dedree
Angle of elevation: tangent angle = opposite/adjacent and by rearranging the given formula will help to solve the problem
Angle of elevation = 300/50 = 6 tan-1(6) = 80.53767779 degrees or 800 32' 15.64''
18.6 m/52.6 degrees tan= 14.2
Using trigonometery if you know the length of its shadow and angle of elevation
you could do a model showing the angle of elevation and angle of depression of a building