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vx = 30.0 * cos 60 = 15.0 m/s

vy = 30.0 * sin 60 = 25.9 m/s

ax = -9.81 m/s/s; ay = 0 m/s/s

At the maximum height, vf = 0 m/s

0 = 25.92 - 19.62dy

dy = 34.1 m

Range I don't know

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Q: A cannon shoots a projectile at an angle of 60 degrees above the horizontal with an initial speed of 30.0 ms. Calculate the maximum height of the projectile and its range?
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