vx = 30.0 * cos 60 = 15.0 m/s
vy = 30.0 * sin 60 = 25.9 m/s
ax = -9.81 m/s/s; ay = 0 m/s/s
At the maximum height, vf = 0 m/s
0 = 25.92 - 19.62dy
dy = 34.1 m
Range I don't know
reduction ratio= initial cross sectional area/final cross sectional area
The component form of a vector lists the horizontal and vertical change from the initial point to the terminal point. * * * * * The axes need not be perpendicular to one another. They just need to be non-parallel.
The initial length is 0.2 cm Initial temperature is 30 degrees C and final temperature is 60 degrees C. he difference in temperature is 30 degrees. Let "e" be the linear coefficient of expansion of the steel rod in cm per degree C (you can find this from the specifications for the particular steel), then the expansion is 0.2 x e x 30 cm To find the total new length we have to add the original length which is 0.2 cm Hence new length is 0.2 + (0.2 x e x 30) cm And that is (0.2) x (1 + e x 30) cm
L/(L-85) = tan60/tan30 = 3 (L = initial distance of man from base of tower)L = 3L-255 so 2L = 255 and L = 127.5 giving height = 127.5 tan30 = 73.6 m
The equivalent of the x-axis
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
A projectile has an initial forward velocity.
You cannot. You need to know either the initial speed or angle of projection (A).
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Yes. They will both initially be moving at the same speed.
A projectile has an initial forward velocity.
A projectile has an initial forward velocity.
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.