vx = 30.0 * cos 60 = 15.0 m/s
vy = 30.0 * sin 60 = 25.9 m/s
ax = -9.81 m/s/s; ay = 0 m/s/s
At the maximum height, vf = 0 m/s
0 = 25.92 - 19.62dy
dy = 34.1 m
Range I don't know
reduction ratio= initial cross sectional area/final cross sectional area
The component form of a vector lists the horizontal and vertical change from the initial point to the terminal point. * * * * * The axes need not be perpendicular to one another. They just need to be non-parallel.
The initial length is 0.2 cm Initial temperature is 30 degrees C and final temperature is 60 degrees C. he difference in temperature is 30 degrees. Let "e" be the linear coefficient of expansion of the steel rod in cm per degree C (you can find this from the specifications for the particular steel), then the expansion is 0.2 x e x 30 cm To find the total new length we have to add the original length which is 0.2 cm Hence new length is 0.2 + (0.2 x e x 30) cm And that is (0.2) x (1 + e x 30) cm
L/(L-85) = tan60/tan30 = 3 (L = initial distance of man from base of tower)L = 3L-255 so 2L = 255 and L = 127.5 giving height = 127.5 tan30 = 73.6 m
The equivalent of the x-axis
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the time of flight and then multiply it by the horizontal component of the initial velocity to find the horizontal distance traveled.
The horizontal distance traveled by a projectile is determined by the initial velocity of the projectile, the angle at which it was launched, and the time of flight. It can be calculated using the equation: horizontal distance = (initial velocity * time * cosine of launch angle).
The horizontal speed of the projectile remains constant as there is no force acting in the horizontal direction to change it. Therefore, the horizontal speed of the projectile after 3 seconds will remain at 4 m/s.
The horizontal motions of a projectile are independent of its vertical motion. This means that the horizontal velocity remains constant and unaffected by gravity. Additionally, the horizontal distance traveled by a projectile is determined by the initial horizontal velocity and the time of flight.
A half projectile refers to the projectile motion of an object where it is launched at an angle of 45 degrees to the horizontal. This angle maximizes the range of the projectile for a given initial velocity, making it travel the furthest distance before hitting the ground. The path of the projectile is a parabolic curve.
For a projectile launched at an angle θ, the range is the same for angles of θ and (90-θ) degrees. This is because the horizontal and vertical components of the initial velocity are the same for these angles, resulting in the same horizontal range.
-- the initial horizontal speed of the projectile -- the time it remains in flight before it hits the ground
it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection.
The formula for the horizontal distance traveled by a horizontally launched projectile is: range = initial velocity * time. This formula assumes that there is no air resistance and that the projectile is launched horizontally.
To determine how far a projectile travels horizontally, you need to know the initial velocity of the projectile, the angle at which it was launched, and the acceleration due to gravity. Using these values, you can calculate the horizontal distance traveled using the projectile motion equations.
The proof that 45 degrees provides the maximum range for projectile motion is based on the fact that at this angle, the horizontal and vertical components of the initial velocity are equal. This results in the projectile traveling the farthest distance before hitting the ground.
To determine the launch velocity of a projectile, you can use the projectile motion equations. By measuring the initial height, horizontal distance traveled, and the angle of launch, you can calculate the launch velocity using trigonometry and kinematic equations.