L/(L-85) = tan60/tan30 = 3 (L = initial distance of man from base of tower)
L = 3L-255 so 2L = 255 and L = 127.5 giving height = 127.5 tan30 = 73.6 m
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
height = 15 ft base = 20 ft angle of elevation = arctan (15/20) = 36.87 degrees
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
A girl 1.2 m in height is 25 m away from a tower 18 m high. What value is the angle of elevation of the top of the tower from her eyes?
the height to which something is elevated or to which it rises: The elevation of the tower is 80 feet. :)
Using the sine rules in trigonometry the height of the mountain works out as 3704 meters in height to the nearest whole number.
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
By drawing a sketch from the given information then using triangulation and trigonometry the height of the mountain works out as 3704.435 meters rounded to three decimal places.
Using the formula: tangent = opposite/adjacent whereas tangent angle = height/ground distance, will help to solve the problem
height = 15 ft base = 20 ft angle of elevation = arctan (15/20) = 36.87 degrees
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
A girl 1.2 m in height is 25 m away from a tower 18 m high. What value is the angle of elevation of the top of the tower from her eyes?
The flagpole is 15.92 metres, approx.
If the base of the elevation is at a distance d from the observer, then the highest point is at a height = d*tan(angle of elevation)
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft