V1 = lwh
V1 = 3 x 2.5 x 2
V1 = 15 ft^3
V2 = (2 x 3)(2.5)(2 x 2)
V2 = 6 x 2.5 x 4
V2 = 60 ft^3
percent of increase = (V2 - V1)/V1 = (60 - 15)/15 = 45/15 = 3
Thus the volume is changed by 300%.
The volume will be doubled.
The area of the triangle would double
It is quadrupled.
The area is multiplied by 4, not doubled.
quadrupled. :)
The volume will be doubled.
If the base stays the same, the area is also doubled.
A 3-Dimensional box's volume will double for each dimension that is doubled. i.e. if just the height, length or depth are doubled, the volume increases 200%, if 2 of those dimensions are doubled the volume increases by 400%. if all 3 are double the volume increases by 800%.
300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:
if length and width are doubled then the volume should mulitiply by 8
The area of the triangle would double
It is quadrupled.
When you change the linear size it changes the areas by the square and the volume of the cube.
The area is multiplied by 4, not doubled.
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.
The tree took 19 years to reach half its maximum height. Since it doubled in height each year, it was half of its maximum height in the year prior to reaching its full height.
The area gets doubled.