A cardboard box has a length of 3 feet height of 2.5 feet and depth of 2 feet if the length and depth are doubled by what percentage does the volume of the box change?

Answer 1

V1 = lwh

V1 = 3 x 2.5 x 2

V1 = 15 ft^3

V2 = (2 x 3)(2.5)(2 x 2)

V2 = 6 x 2.5 x 4

V2 = 60 ft^3

percent of increase = (V2 - V1)/V1 = (60 - 15)/15 = 45/15 = 3

Thus the volume is changed by 300%.