4.84
You take y liters of the solution and put it into a bucket or container. You then put y (same amount as before) liters of water in the same container, and voila! You now have a container with 50 percentile solution, 50 percentile water.
add 4 parts water per part solution
Well, isn't that a lovely little problem to solve? To decrease the concentration from 25% to 20%, we need to dilute the solution. Since the concentration is decreasing by 5%, we can calculate that we need to add 60 liters of water to the 300 liters of solution to achieve the desired concentration of 20%. Just like painting, a little change can make a big difference in creating the perfect mixture.
25%
Well, it's been awhile since I've done this but my answer would be 24 liters must evaporate to make a 5% solution. 60 * .03 = 1.8 ~ That's what you have. The 1.8 is how many liters of salt you have. 60 = x ~ Replace 60 with x. x * .05 = 1.8 ~ The percentage of salt is now 5 but you still have 1.8 liters. 1.8/.05=36 ~ algebra... 60 - 36 = 24 ~ Total minus how much will remain gives you the total that must evaporate. I know you could have followed them easily enough without the notes. They were more for me so I knew I'd done it correctly. :-) Hope it's right and .
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
0.1125% of polymer solution.
If you have a solution that is 50% water and 50% hydrogen peroxide, you would have equal volumes of each component. So if you have 1 liter of this solution, you would have 0.5 liters of water and 0.5 liters of hydrogen peroxide.
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
You take y liters of the solution and put it into a bucket or container. You then put y (same amount as before) liters of water in the same container, and voila! You now have a container with 50 percentile solution, 50 percentile water.
Jorge needs to add 2 liters of water to the 30% acid solution to make a 25% acid solution. This can be calculated using a dilution formula: initial acid amount / final total amount = final acid concentration.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
90 ml of dextrose and 4.41 litres of water.
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.