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If the angle of elevation of the sun is 53 degrees when a flagpole casts a shadow of 12 m then the height of the flagpole is?
Use the Tangent function
Tan(angle) = opposite(height) / adjacent(shadow)
Substituting
Tan )53) = height/ 12m
Algebraically rearrange
height = 12m X Tan (53)
NB Make sure your calculator is in 'Degree' Mode.
Then type in '12' 'X' , '(' , 'Tan', '53', ')' , '=', The answer should 'pop ip' pm the screen .
height = 15.92453786...m
Approx. ht. ~ 15.92 m ( 2 d.p.).
What else can I help you with?
What is the angle of elevation of the sun if a 55 foot tall flag pole casts a 16 foot long shadow?
To find the angle of elevation of the sun, we can use the tangent function in trigonometry. The angle of elevation (θ) can be calculated using the formula: tan(θ) = opposite/adjacent. Here, the height of the flagpole (55 feet) is the opposite side, and the length of the shadow (16 feet) is the adjacent side. Thus, θ = arctan(55/16), which gives an angle of approximately 74.74 degrees.
Find the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 34 m long?
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
what is the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 32.4 m long?
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
What is the angle of elevation of the sun when a flagpole M tall cast a shadow m long?
The angle of elevation of the sun can be determined using the tangent function in trigonometry. Specifically, if the height of the flagpole is ( M ) and the length of the shadow is ( m ), the angle of elevation ( \theta ) can be calculated using the formula ( \tan(\theta) = \frac{M}{m} ). To find the angle, use ( \theta = \arctan\left(\frac{M}{m}\right) ). This angle represents how high the sun is in the sky relative to the horizontal ground.
When the shadow of a flagpole is 31.2m long a 1.6m fencepost casts a shadow 2.6m long how tall is the flagpole?
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
Suppose you know the height of a flagpole on the beach of the Chesapeake Bay and that you know the length of its shadow How do you calculate the angle of elevation?
If you also know its shadow then you can work out the angle of elevation
What is the angle of elevation to the nearest degree of the sun if a 54 foot flagpole casts a shadow 74 feet long?
36 degrees
If a flagpole casts a shadow of 7.7m and a meter stick casts a shadow of 1.4m how tall is the flagpole?
To find the height of the flagpole, you can use the concept of similar triangles. The ratio of the height of the flagpole to the length of its shadow should equal the ratio of the height of the meter stick (1 meter) to its shadow (1.4 meters). Therefore, the height of the flagpole can be calculated as follows: [ \text{Height of flagpole} = \frac{7.7 , \text{m}}{1.4 , \text{m}} \times 1 , \text{m} \approx 5.5 , \text{m}. ] Thus, the flagpole is approximately 5.5 meters tall.
When the angle of elevation to the sun is 26 degrees a flagpole casts a shadow that is 82 feet long. How tall is the flag pole?
It is nearly 40 feet
When is the shadow equal in length to your height?
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
A flagpole casts a ten meter shadow at the same time as a six meter statue beside it casts a two meter shadow What is the height of the flagpole?
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
A flagpole casts a shadow of 40 ft nearby a 10-ft tree casts a shadow of 2 ft what is the height of the flagpole?
Ten is to two as 40 is to x, yielding: 200ft.
How tall is a building with a 73 ft shadow when elevation of the sun is 31 degrees?
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
What is the height in feet of a flagpole which casts a 6-foot shadow when a 6-foot man cast a 3-foot shadow?
Using trigonometry its height is 12 feet
Find the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 34 m long?
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
If a 30 foot flagpole casts a 12 foot shadow how tall is a mailbox casting a 18 inch shadow?
First find the angle of elevation by using the tangent ratio formula:tangent = opposite (the flagpole)/adjacent (the shadow)tangent = 30/12 = 68.19859051 degreesThen rearrange the formula to find the height of the mailbox:height of mailbox = 18*tangent 68.19859051 = 44.99999......Therefore: height of mailbox = 45 inches to the nearest inch.Or,Since we have two similar right triangles whose legs are the 30 feet flagpole and its 12 feet shadow, the length x of mailbox and its 18 inches shadow, we have:18 in/x = 12 ft/30 ft (cross multiply)(12)(x) = (30)(18 in)12x = 540 in (divide by 12 to both sides)x = 45 in
what is the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 32.4 m long?
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
