The flagpole is 15.92 metres, approx.
The angle of elevation of the sun can be determined using the tangent function in trigonometry. Specifically, if the height of the flagpole is ( M ) and the length of the shadow is ( m ), the angle of elevation ( \theta ) can be calculated using the formula ( \tan(\theta) = \frac{M}{m} ). To find the angle, use ( \theta = \arctan\left(\frac{M}{m}\right) ). This angle represents how high the sun is in the sky relative to the horizontal ground.
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
If you also know its shadow then you can work out the angle of elevation
36 degrees
To find the height of the flagpole, you can use the concept of similar triangles. The ratio of the height of the flagpole to the length of its shadow should equal the ratio of the height of the meter stick (1 meter) to its shadow (1.4 meters). Therefore, the height of the flagpole can be calculated as follows: [ \text{Height of flagpole} = \frac{7.7 , \text{m}}{1.4 , \text{m}} \times 1 , \text{m} \approx 5.5 , \text{m}. ] Thus, the flagpole is approximately 5.5 meters tall.
It is nearly 40 feet
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Ten is to two as 40 is to x, yielding: 200ft.
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
Using trigonometry its height is 12 feet
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
5