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Find the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 34 m long?
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
what is the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 32.4 m long?
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
When the shadow of a flagpole is 31.2m long a 1.6m fencepost casts a shadow 2.6m long how tall is the flagpole?
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
If a tree casts a shadow of fifteen meters long how tall is the tree?
Not enough information has been given to solve this problem such as: What is the angle of elevation?
A tree 40 feet high casts a shadow 58 feet long find the measure of the angle of elevation of the sum?
To find the angle of elevation of the sun, we can use the tangent function. The tangent of an angle is equal to the opposite side (height of the tree) divided by the adjacent side (length of the shadow). So, tan(angle) = height of the tree / length of the shadow. Plugging in the values, we get tan(angle) = 40 / 58. Taking the arctan of both sides gives us the angle, so the angle of elevation of the sun is approximately 33.56 degrees.
Suppose you know the height of a flagpole on the beach of the Chesapeake Bay and that you know the length of its shadow How do you calculate the angle of elevation?
If you also know its shadow then you can work out the angle of elevation
What is the angle of elevation to the nearest degree of the sun if a 54 foot flagpole casts a shadow 74 feet long?
36 degrees
When the angle of elevation to the sun is 26 degrees a flagpole casts a shadow that is 82 feet long. How tall is the flag pole?
It is nearly 40 feet
When is the shadow equal in length to your height?
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
A flagpole casts a ten meter shadow at the same time as a six meter statue beside it casts a two meter shadow What is the height of the flagpole?
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
A flagpole casts a shadow of 40 ft nearby a 10-ft tree casts a shadow of 2 ft what is the height of the flagpole?
Ten is to two as 40 is to x, yielding: 200ft.
How tall is a building with a 73 ft shadow when elevation of the sun is 31 degrees?
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
What is the height in feet of a flagpole which casts a 6-foot shadow when a 6-foot man cast a 3-foot shadow?
Using trigonometry its height is 12 feet
Find the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 34 m long?
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
If a flagpole cast a shadow of 7.7m and a pole cast a shadow of 1.2m how tall is the flagpole?
5
what is the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 32.4 m long?
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
If a 30 foot flagpole casts a 12 foot shadow how tall is a mailbox casting a 18 inch shadow?
To solve this problem, we can set up a proportion using the similar triangles formed by the flagpole and its shadow, and the mailbox and its shadow. The height of the flagpole to its shadow is 30 feet to 12 feet, which simplifies to 5:2. Using this ratio, we can determine the height of the mailbox by setting up the proportion 5/2 = x/1.5 (converting 18 inches to feet). Solving for x, the height of the mailbox would be 3.75 feet.
