6x-14
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.
The perimeter is 18 feet.
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
It depends on what information you do have. The length and area, the length and diagonal, the length and perimeter, etc. Each set generates a different answer.
call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
Perimeter of rectangle = 2 x (Length + Width) = 2 x (L + 18) or = (2L + 36) centimetres.
The perimeter of a rectangle is not sufficient to determine its length.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter