l=3w
Perimeter (p) = 2*(l+w) = 56
2*(3w+w)=56
2*4w=56
8w=56
w=7 inches
l=3w = 3*7 = 21 inches
the length is equal to 160,083
63 feet
The rectangle is 9 inches wide X 27 inches long. Clue: width is X; length is 3 times width (3X). Perimeter is width plus length times two (X + 3X times 2 = 8X). 8X = 72; X = 9. 3X = 27. Proof: 9 + 9 (2sides) +27 + 27 (2 lengths) = 72.
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
Let the length be 2x-3 and the width be x: 2(length+width) = perimeter 2(2x-3+x) = 52 inches 4x-6+2x = 52 4x+2x = 52+6 6x = 58 x = 9 and 2/3 Therefore: length = 16 and 1/3 inches and width = 9 and 2/3 inches Check: 2(16+1/3+9+2/3) = 52 inches
Width = 9 inches Length = 30 inches
That would be 3 x 9 inches.
the length is equal to 160,083
63 feet
15 feet.
Width: 8.5 Length: 25.5
The rectangle is 9 inches wide X 27 inches long. Clue: width is X; length is 3 times width (3X). Perimeter is width plus length times two (X + 3X times 2 = 8X). 8X = 72; X = 9. 3X = 27. Proof: 9 + 9 (2sides) +27 + 27 (2 lengths) = 72.
call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x
dont is answer
64 meters
L + W = 28/2 = 14 L = 3 + 3W, so 3 + 3W + W = 14 ie 4W = 11 so width is 2¾" and length is 11¼"
Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2