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It could be: 4n = 20 and so n = 5 feet

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Q: A squares side is n feet long and its perimeter is 20 feet write an equation for the perimeter of the square?
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If the perimeter of a rectangular closet is 26 feet. If the length is increased by 4 feet and the width is increased by 3 feet the area of the closet will be 96 square feet. Find the dimensions?

You need to write two equations with two variables each, for the two facts. Remembering that the perimeter is the sum of the lengths of all the sides:Write an equation for the perimeter of the original rectangle:perimeter = 2(length + width)26 = 2(l+w) (equation 1)Write an equation for the area of the increased rectangle:A = length x widthA = (l+4)(w+3) (equation 2)Solve the two equations simultaneously; and you'll get the width and length of the original rectangle.


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A rectangle has a perimeter of 10 ft Write the area A of the rectangle as a function of the length of one side x of the rectangle?

This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.


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What is the hypotenuse and perimeter of a right angle triangle when one side is greater than the other side by 45.5 cm and having an area of 2535 square cm showing all work in step by step stages?

As an intermediate step, calculate the two sides adjacent to the right angle first. Once you have that, you can easily calculate the hypotenuse and the perimeter.You'll have to write an equation to calculate the sides. Use the equation for the area of a triangle. I suggest you set:"x" for one side"x + 45.5" for the other sideAnother Answer:-1 Let the sides be x+45.5 and x2 0.5*(x+45.5)*x = 2535 which transposes to: x2+45.5x-5070 = 03 Solving the above quadratic equation gives x a positive value of 524 So sides are 52+45.5 = 97.5 cm and 52 cm5 Using Pythagoras: 97.52+522 = 12,210.252 and its square root is 110.56 Hypotenuse = 110.5 cm7 Perimeter = 97.5+52+110.5 = 260 cm

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Here is what you are supposed to do: * Convert to consistent units. For example, convert the cm to mm. * Write an equation for the diagonal (in terms of length and width). Replace the known diagonal. * Write an equation for the area, in terms of length and width. * Solve the two equations simultaneously. * Calculate the perimeter.


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If the perimeter of a rectangular closet is 26 feet. If the length is increased by 4 feet and the width is increased by 3 feet the area of the closet will be 96 square feet. Find the dimensions?

You need to write two equations with two variables each, for the two facts. Remembering that the perimeter is the sum of the lengths of all the sides:Write an equation for the perimeter of the original rectangle:perimeter = 2(length + width)26 = 2(l+w) (equation 1)Write an equation for the area of the increased rectangle:A = length x widthA = (l+4)(w+3) (equation 2)Solve the two equations simultaneously; and you'll get the width and length of the original rectangle.


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What is the perimeter of a rectangle whose diagonal is 17.55 cm with an area of 109.35 square cm showing key aspects of work?

Here are the key aspects of work; I'll leave the details of the calculation to you. 1) Write an equation for the area, in terms of variables "w" and "h" (for width and height). 2) Write an equation for the length of the diagonal, in terms of "w" and "h". (Hint: Use the Pythagorean Theorem.) 3) Solve the two equations. 4) Calculate the perimeter, based on length and width.


What are the dimensions of a rectangle that has an area of 600 square cm and a perimeter of 1 m showing work?

I suggest that you do the following:* Convert the meters to centimeters, to have compatible units.* Write the equation for the area of the rectangle. Replace the variable "a" (area) with the known area.* Write the equation for the perimeter of a rectangle. Replace the variable for the perimeter with the known perimeter (in cm).* Use any method to solve the simultaneous equations.Another Answer:-Let the dimensions be x and yIf: 2x+2y = 100 then x+y = 50 and x = 50-yIf: xy = 600 then (50-y)y = 600 and so 50y-y2-600 = 0Solving the quadratic equation: y = 20 or y = 30Therefore by substitution the dimensions are: when y = 20 cm then x = 30 cm