Use the tangent ratio:
23*tan(23) = 9.762920773
Answer: 10 meters to the nearest meter
Tan60= 25/Height. Height = 25/Tan60 = 14.43
It is: tan(52)*9 = 11.519 meters rounded to three decimal places
Using the tangent ratio height of telegraph pole is 55 feet to the nearest integer.
It is: 27.35 degrees rounded to two decimal places
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
Tan60= 25/Height. Height = 25/Tan60 = 14.43
It is: tan(52)*9 = 11.519 meters rounded to three decimal places
Using the tangent ratio height of telegraph pole is 55 feet to the nearest integer.
If you also know its shadow then you can work out the angle of elevation
By means of trigonometry if you know the angle of elevation or by comparing it with a nearby object if you know its height and shadow length.
Using trigonometery if you know the length of its shadow and angle of elevation
tan(36) = H/58 where H is the height of the tower. So H = 58*tan(36) = 42 feet.
To find the length of the shadow of the CN Tower when the angle of elevation is 50 degrees, you can use the tangent function. The formula is: shadow length = height / tan(angle). Thus, the shadow length would be approximately 553 meters / tan(50°), which is about 553 meters / 1.1918, resulting in a shadow length of approximately 464 meters.
Not enough information has been given to solve this problem such as: What is the angle of elevation?
It is: 27.35 degrees rounded to two decimal places
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
To find the angle of elevation of a rod given the ratio of its height to the length of its shadow as (1 : \sqrt{3}), we can use the tangent function. The tangent of the angle of elevation ( \theta ) is equal to the ratio of the opposite side (height of the rod) to the adjacent side (length of the shadow). Therefore, ( \tan(\theta) = \frac{1}{\sqrt{3}} ). This corresponds to an angle of ( 30^\circ ).