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Since AB and AC are tangent to the circle O, it seems that they both are drawn from the same outside point A. As tangents to a circle from an outside point are congruent, AB ≅ BC.

Also, a tangent is perpendicular to radius drawn to point of contact. So that OB and OC are congruent radii. Therefore, the perimeter of the quadrilateral ABOC equals to

P = 2(12 cm) + 2(5 cm) = 34 cm.

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Q: Ab and ac are tangents to a circle with centre o and radius 5cmif ac equals 12cmfind the perimeter of quadrilateral aboc?
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