Q: How do you draw tangents to a circle without using its centre?

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Common Tangents Some common tangents of two circles can be drawn.You can find that the number of them varies by the condition of the distance and radii of two circles.Using the applet of Common Tangents, try to explore this relation to the common tangents. Using the applet of Common Tangents In this applet you can explore the number of common tangents, dragging to change the radii or to move the circles.The button of@"Init"@is for replacing the figure in the initial state.If you click the button of@"Auto",@the circles are moving automatically, and then you can enjoy their performance.

Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.

Tangents stem from the origin: (0, 0) Circle equation: x^2 +y^2 -6x +4y +10 = 0 Completing the squares: (x+2)^2 +(y-3)^2 -4 -9 +10 = 0 So: (x+2)^2 +(y-3)^2 = 3 which is the radius squared Centre of circle: (-2, 3) Distance from (-2, 3) to (0, 0) = 13 which is distance squared Lengths of tangents using Pythagoras: 13-3 = 10 => square root of 10 Take note that the distance from (-2, 3) to (0, 0) is actually the hypotenuse of a right angle triangle.

Using 3.14 as Pi the area of circle is: 0

x2+y2-4x-6y-3 = 0 Using the appropriate formula it works out as:- Centre of circle: (2, 3) Radius of circle: 4.

Related questions

There are many angles inside a circle. You have inscribed angles, right angles, and central angles. These angles are formed from using chords, secants, and tangents.

Stuff like circle things!

Common Tangents Some common tangents of two circles can be drawn.You can find that the number of them varies by the condition of the distance and radii of two circles.Using the applet of Common Tangents, try to explore this relation to the common tangents. Using the applet of Common Tangents In this applet you can explore the number of common tangents, dragging to change the radii or to move the circles.The button of@"Init"@is for replacing the figure in the initial state.If you click the button of@"Auto",@the circles are moving automatically, and then you can enjoy their performance.

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Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.

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There are 2,000 metres in a circle where the circumference (length around it) is 2km. There are 6,283 metres in the circle circumference (c) where the diameter (d - straight line that passes through the centre and whose endpoints are on the circle) is 2km. Using the formula c = Pi * d. Pi = 3.1415 There are 12,566 metres in a circle circumference (c) where the radius (r - line segment from the centre of a circle to the perimeter) is 2km. Using the formula c = pi * 2r. Pi = 3.1415. There are 12,566,00 m^2 in a circle with a radius of 2km. Using the formula area = pi * (r)^2

Tangents stem from the origin: (0, 0) Circle equation: x^2 +y^2 -6x +4y +10 = 0 Completing the squares: (x+2)^2 +(y-3)^2 -4 -9 +10 = 0 So: (x+2)^2 +(y-3)^2 = 3 which is the radius squared Centre of circle: (-2, 3) Distance from (-2, 3) to (0, 0) = 13 which is distance squared Lengths of tangents using Pythagoras: 13-3 = 10 => square root of 10 Take note that the distance from (-2, 3) to (0, 0) is actually the hypotenuse of a right angle triangle.

Draw two diameters perpendicular to each other. Draw a smaller circle with the same centre such that the radius of the inner circle is 'r' and the radius of the outer circle is 'r√2.' [Or, the radius of the outer circle is R and the radius of the inner circle is R/√2.]

Using 3.14 as Pi the area of circle is: 0

yes it is possible by using a coin

You can't. However, you can divide it into seven, like so: Make the lines make a triangle in the middle of the circle, rather than making them meet at the centre.