6.20 feet
Use Pythagoras to find the perpendicular height of the triangle: 132-52 = 144 and the square root of this is the height of the triangle which is 12 cm Area = 1/2*12*10 = 60 square cm
assuming its an isosceles triangle, then its 16 cm high
By using Pythagoras' theorem.
In a isosceles triangle, the altitude is also a median. If we draw the altitude, then two congruent right triangles are formed, with hypotenuse length of 12m and base length 5 m (10/2). So the length of hypotenuse, by the Pythagorean theorem is h^2 = 12^2 - 5^2 h = √(144 - 25) h = √119 h ≈ 10.9
The theorem is only true if the base is the side of different length.To see this consider the right angled isosceles triangle with sides 1, 1 and √2. If one of the sides of length 1 is the base, the height is obviously the other side of length 1, but it clearly does not meet the base at its mid-point to make it a median.So with an isosceles triangle ABC with sides AB & AC equal, angles ABC & ACB equal and side BC the base, we need to prove that the point X where the height (AX) meets BC is such that BX = CX.Consider triangles AXB and AXC.Angle AXB is a right angle, as is AXC (since AX is a height of triangle ABC).Side AB is the hypotenuse of triangle AXB; AC is the hypotenuse of triangle AXC; they are known to be equal (from isosceles triangle ABC)Side AX is common to both trianglesThus triangles AXB and AXC are congruent since we have a Right-angle, Hypotenuse, Side match.Thus XB must be the same length as XC, that is X is the mid-point of BC.As X is the mid-point of BC, AX is the median.
When it's a right triangle and it's sitting on one of the congruent sides.
Yes if the isosceles triangle is a right isosceles triangle because that leg opposite the hypotenuse is the height
When it has a 90 degree angle and 2 equal angles of 45 degrees
Use Pythagoras' theorem: 82-52 = 39 and the square root of this is 6.244997998 or 6.245 feet in height to 3 d.p.
An isosceles triangle has 2 equal base angles and its height is perpendicular from its apex to the centre of its base
To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
legs Base and height are equal in langth
Use pythagoras' therom: 82-52 = 39 and the square root of this is 6.244997998 height = 6.245 ft to 3 d.p.
An isosceles, possibly equilateral, triangle
Area of any triangle is: 0.5*base*perpendicular height
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
The formula is: Area = base * height. With an isosceles triangle, two of the angles are congruent and their opposite sides are congruent. There is one remaining angle (that will be referred to as the top angle) and its opposite side (the base). You will probably have to drop a perpendicular line from the top angle to the base. This will bisect the base into two equal parts. Also, you now have two congruent right triangles. It depends on what you know with this triangle in order to find its height and/or base. However, use the Pythagorean Theorem and I'm sure you can work it out.