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Discuss the validity of extrapolating the acceleration value to an angle of 90?
Extrapolate the experimental values of acceleration, vs. angle of the incline, to find the acceleration when the angle of inclination = 90 degrees. The acceleration at 90 degrees will equal 9.81 m/s/s, since this is the free-fall acceleration.
What is the the best catapult launch angle?
in a frictionless vacuum, 45°, otherwise (on earth), aim to have the projectile release when the arm is at about 40° from the base
What does a inclined plane look like?
An inclined plane is just what its name suggests. It is an plane that is inclined (anlged) to be steep. To make an inclined plane, draw a right angle (90 degrees) and connect the two extended lines with a diagonal line. It should look like a triangle.
What surface is 90 degrees to a horizontal surface?
Perpendicular
What angle for firing projectiles gives longest time?
45 degrees to the horizontal will give the maximum flight time for a projectile. If a projectile was fired at 90 degrees to the horizontal, (straight upwards) the projectile will go straight upwards (ignoring the shape, form and aerodynamic properties of the projectile). Likewise if you were to fire a projectile at 0 degrees to the horizontal, the projectile would follow said course, IF gravity was not in effect; a projectile needs some form of vertical velocity to overcome gravity. Hence why 45 degrees will give you the longest distance and consequently flight time.
A child slides down a frictionless slope at 25 degrees to the horizontal Calculate the child's acceleration down the slope?
a(child acceleration)=g(gravitational acceleration)*sin25=4.144 m/s2
How do you resolve a horizontal force of 40 newtons into two perpendicular directions one of them inclines by 30 degree with the horizontal and upwards?
-- The component that's inclined 30 degrees above the horizontal is[ 20 sqrt(3) ] = about 34.641 newtons. (rounded)-- The other component is inclined 60 degrees below the horizontal,and its magnitude is 20 newtons.
What is Trajectory?
A trajectory is the angle made with the horizontal when a projectile is fired. Suppose the projectile is a cannon ball. Assuming air is frictionless, that cannon ball will travel the greatest distance if the trajectory is 45 degrees from horizontal.
A boy is tobogganing down a smooth slope inclined at 20 degrees to horizontal find his acceleration assuming resistances can be neglected?
The acceleration of the boy can be found using the equation a = g * sin(θ), where g is the acceleration due to gravity (approximately 9.81 m/s^2) and θ is the angle of the slope (20 degrees). Therefore, the acceleration of the boy would be a = 9.81 m/s^2 * sin(20 degrees) ≈ 3.36 m/s^2.
What a step graph?
A graph which consists of short straight lines which keep changing direction. Example : a graph line which is inclined at say, 30 degrees to a horizontal, then changes direction instantly to a line which is say, inclined at 60 degrees to the horizontal , etc. If the shape of a graph is not a series of straight lines joined to each other, then it is not a step graph.
A body slides down a frictionless plane and during the third second after starting from rest it travels 19.4m what is the angle of inclination of the plane?
Using the equation of motion for an object sliding down a frictionless incline, we have d = (1/2)at^2, where d is the distance traveled, a is the acceleration, and t is the time. Solving for acceleration a gives a = (2d) / t^2. Substituting the given values, a = (2*19.4) / 3^2 = 12.89 m/s^2. Since a = gsinθ, where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of inclination, we can solve for θ: 12.89 = 9.81sinθ. Therefore, θ = sin^(-1)(12.89 / 9.81) ≈ 53.82 degrees.
What is the acceleration of the 25 kg crate which is pulled by a rope along a frictionless surface at an angle of 30 degrees above the horizontal if the tension on the rope is 120 N?
the force acting down the slope = sin 30 * 25 (kg) = 0.5 * 25 = 12.5 kg = (12.5 * 9.806 ) 122.575 newtons = resultant force of (122.575-120 ) 2.575 newtons downhill giving downhill acceleration of (using f=ma) 0.103 (m/s)/s
What is the horizontal force when a force of 20N is inclined at an angle of 30 to horizontal?
The horizontal force can be calculated using the formula Fhorizontal = Fcos(θ), where F is the given force (20N) and θ is the angle of inclination (30 degrees). Plugging in the values, we get Fhorizontal = 20N x cos(30) ≈ 17.3N.
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial magnitude of the velocity is sqrt(5) times the horizontal component. This results in a velocity vector that is inclined at an angle of arctan(2) ≈ 63.43 degrees with respect to the horizontal.
What is the minimum force required to prevent a ball weighing 12 lbs from rolling down a ramp which is inclined 60 degrees with a horizontal?
12 x sin 60 = 11.08 pounds
What is The earths axis is inclined at?
23.5 degrees.
Frictionless 30.0 incline What is the approximate magnitude of force f?
The magnitude of force f can be calculated using the equation f = mgsin(theta), where m is the mass of the object, g is the acceleration due to gravity, and theta is the angle of the incline. Given the angle of 30 degrees, the force can be calculated by plugging in the values of mass and acceleration due to gravity.
