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Let a, b, and c be the width, height, and diagonal of the rectangle.
Pythagorus' theorem applies to the rectangle as follows: a^2 + b^2 = c^2
substitute for 'a' from Pythagoruss theroem: a = sqrt(c^2 - b^2)
Therefore, Area = a * b = b * sqrt(c^2 - b^2) <-- we don't have enough information to solve for Area (we don't know either a or b).
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Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
What is the length of a diagonal of a rectangle 24 inches long and 10 inches wide?
Using Pythagoras' theorem it is 26 inches in length
Would A rectangle is 7 cm wide and 10cm long.find the lenght of a diaonal of the rectangle?
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
How do you calculate the diameter of a rectangle?
A rectangle does not have a diameter, as such, but the diagonal is similar enough. If the sides of a rectangle are x cm and y cm then, using Pythagoras's theorem, the diagonal is sqrt(x2 + y2) cm.
The diagonal of rectangle is 50 cm its breadth is 30 cm then the perimeter is?
Using Pythagoras theorem its length is 40 cm and so 2(40+30) = 140 cm which is its perimeter
