Let a, b, and c be the width, height, and diagonal of the rectangle.
Pythagorus' theorem applies to the rectangle as follows: a^2 + b^2 = c^2
substitute for 'a' from Pythagoruss theroem: a = sqrt(c^2 - b^2)
Therefore, Area = a * b = b * sqrt(c^2 - b^2) <-- we don't have enough information to solve for Area (we don't know either a or b).
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
Using Pythagoras' theorem it is 26 inches in length
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
A rectangle does not have a diameter, as such, but the diagonal is similar enough. If the sides of a rectangle are x cm and y cm then, using Pythagoras's theorem, the diagonal is sqrt(x2 + y2) cm.
The diagonal length of a rectangular solid can be calculated using the formula ( d = \sqrt{l^2 + w^2 + h^2} ), where ( l ), ( w ), and ( h ) are the length, width, and height of the solid, respectively. This formula derives from the Pythagorean theorem applied in three dimensions. The diagonal represents the longest straight line that can be drawn between two opposite corners of the solid.
You can calculate this using the Pythagorean formula for a right triangle.
The length of the diagonal of an ( a , \text{ft} \times a , \text{ft} ) rectangle can be calculated using the Pythagorean theorem. The diagonal ( d ) is given by the formula ( d = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2} ). Therefore, the length of the diagonal is ( a\sqrt{2} ) feet.
Using Pythagoras' theorem the length of the diagonal is 20 feet
You can't. Suppose for instance your rectangle is 1xA, then the diagonal length is sqrt(1+A**2). But if your rectangle is sqrt(A)xsqrt(A) then your diagonal length is sqrt(2*A). The only thing one can say for sure is that the diagonal length is at least sqrt(2*A).
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
Using Pythagoras' theorem its width is 6 units in length.
About 12.7. (I got it from using the pythagreon theyrom.)
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
Using Pythagoras' theorem it is 26 inches in length
The formula for the area of a rectangle is length x breadth. In order to prove this works, work out an area of a rectangle using that formula.
A rectangle does not have a diameter, only circles or similar obects have diameters. A rectangle has a diagonal which is obtained by joining two opposite corners. Any two adjacent sides of the rectangle together with the diagonal form a right angled triangle and so the length of the diagonal can be derived using Pythagoras's theorem.