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Let a, b, and c be the width, height, and diagonal of the rectangle.
Pythagorus' theorem applies to the rectangle as follows: a^2 + b^2 = c^2
substitute for 'a' from Pythagoruss theroem: a = sqrt(c^2 - b^2)
Therefore, Area = a * b = b * sqrt(c^2 - b^2) <-- we don't have enough information to solve for Area (we don't know either a or b).
What else can I help you with?
Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
What is the length of a diagonal of a rectangle 24 inches long and 10 inches wide?
Using Pythagoras' theorem it is 26 inches in length
Would A rectangle is 7 cm wide and 10cm long.find the lenght of a diaonal of the rectangle?
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
How do you calculate the diameter of a rectangle?
A rectangle does not have a diameter, as such, but the diagonal is similar enough. If the sides of a rectangle are x cm and y cm then, using Pythagoras's theorem, the diagonal is sqrt(x2 + y2) cm.
The diagonal of rectangle is 50 cm its breadth is 30 cm then the perimeter is?
Using Pythagoras theorem its length is 40 cm and so 2(40+30) = 140 cm which is its perimeter
What is the length of a diagonal line in a rectangle 30 feet by 20 feet?
You can calculate this using the Pythagorean formula for a right triangle.
What is the length of a diagonal of a rectangle whose dimensions are 12 by 16 feet?
Using Pythagoras' theorem the length of the diagonal is 20 feet
How do you find the length of rectangle diagonally by using the area given?
You can't. Suppose for instance your rectangle is 1xA, then the diagonal length is sqrt(1+A**2). But if your rectangle is sqrt(A)xsqrt(A) then your diagonal length is sqrt(2*A). The only thing one can say for sure is that the diagonal length is at least sqrt(2*A).
What is length of diagonal line in rectangle 32 feet by 36 feet?
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
How do you find the area of a rectangle given the length and diagonal?
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
A rectangle has a diagonal of 10 and a length of 8. what is its width?
Using Pythagoras' theorem its width is 6 units in length.
What is the diagonal length of a rectangle with the sides of 10 and 8?
About 12.7. (I got it from using the pythagreon theyrom.)
Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
What is the length of a diagonal of a rectangle 24 inches long and 10 inches wide?
Using Pythagoras' theorem it is 26 inches in length
How do you prove the formula for the area of a rectangle?
The formula for the area of a rectangle is length x breadth. In order to prove this works, work out an area of a rectangle using that formula.
How do you get the diameter of a rectangle?
A rectangle does not have a diameter, only circles or similar obects have diameters. A rectangle has a diagonal which is obtained by joining two opposite corners. Any two adjacent sides of the rectangle together with the diagonal form a right angled triangle and so the length of the diagonal can be derived using Pythagoras's theorem.
What is the diagonal length of a 40x40 square?
The diagonal length of a square can be calculated using the formula (d = a\sqrt{2}), where (a) is the length of a side. For a 40x40 square, the diagonal length is (d = 40\sqrt{2}), which is approximately 56.57 units.
