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Area of pipe when thickness of wall inner radius of pipe and length of pipe is given?
For a pipe of uniform radius and thickness, I believe the total surface area would be the Outside surface + Inside surface+ 2 times the surface of the ends. The inside radius(rinner), pipe thickness (t), and pipe length (L) are given.
So you only need to find the outside radius (Rout) and then all areas can be calculated.
The outside radius should be Rout=rinner +t. And note the perimeter of a circle is 2*pi*Radius and area of an annular region (in this case the ends of the pipe) is A= pi*(Rout2 - rinner2)
For the outer pipe surface: Aout=2*pi*(Rout)*L
For the inner pipe surface: Ainner=2*pi*(rinner)*L
For each pipe end: Aend= pi*(Rout2 - rinner2)
So the total surface area of the pipe would be: Aout+ Ainner+2* Aend
Or: Atotal =2*pi*(Rout)*L+2*pi*(rinner)*L+ 2*pi*(Rout2-rinner2)
= pi*[ 2*L*(Rout + rinner)]+(Rout2 - rinner2)
= 2*pi*[ L*( rinner +t + rinner)]+(( rinner +t )2 - rinner2)]
=2*pi*(t+L)(t+2*rinner)
Hopefully that is correct and helps.
What else can I help you with?
What do you mean by internal radius?
It's the radius of a circle or sphere WITH A SHELL(or Thickness); like if an Lid on a jar had a diameter of 11mm across on the outside (top of lid); and was ONE mm thick, then the inside radius would be 5. ie; 11mm outer diameter, minus (-) 1mm thickness (aka; or shell) equals (=) 10mm (inner) diameter; which is a 5mm radius.
How you can find total radius if inner radius and outer radius is given?
You must use the relationship between the inner radius and the outer radius. The relationship could very well be different every time you run into a problem like this, and I can't answer the question this time because you haven't described any relationship between them.
How do you divide a circle into 8 equal parts using 3 lines?
Draw two diameters perpendicular to each other. Draw a smaller circle with the same centre such that the radius of the inner circle is 'r' and the radius of the outer circle is 'r√2.' [Or, the radius of the outer circle is R and the radius of the inner circle is R/√2.]
What is the surface area if a cylindrical ring if its outside diameter is 16 mm and its inside diameter is 10 mm?
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.
A piece of lead pipe of inner diameter 5.72 cm outer diameter 6.67 cm length 40.64 cm has been melted in an open conical pot of radius 25.4 cm altitude 38.1 cm. Find the depth of the molten metal?
Is this taking into consideration the dross content as the metal melts it oxides? and how much does the lead pipe weigh per foot?
What the thickness of the inner core?
The thickness of the inner core is 1,200 km. 1,200 km being the radius of the sphere known as the inner core.
How do you find wall thickness of pipe knowing the outside diameter and inner diameter of pipe?
Outer radius minus inner radius Subtract the inside diameter from the outside diameter, then divide the difference by 2.
Calculate volume of ring?
let the outer radius of the ring be R inner radius r n cross sectional radius be y then the volume of the ring will be (pi)y2 X (pi)(R-r)/2 i.i the cross sectional area multiplied by the length of the ring when it was a line the length is taken at the midpoint of the thickness of the ring = (R-r)/2
What is the length of the inner core?
The inner core of the Earth has a radius of approximately 1,220 kilometers, which makes its diameter around 2,440 kilometers.
How do you find the inside Area of a pipe?
Measure the length of the pipe and the inner Dia of the pipe. 2 x pi x Radius x length is the inner surface area
How can you calculate the weight of a ms hollow pipe 200mm ID 8 mm thickness length 1000 mm?
With the information given in the question you cannot. The volume of the pipe is pi(R2 - r2)*L where R = outer radius = outer diameter*0.5 = ID/2 + thickness = 108 mm r = inner radius = inner diameter*0.5 = ID/2 = 100 mm L = length = 1000 mm Next, to convert volume to mass, you need to multiply by the density. You then need to multiply the mass by the gravitational acceleration to convert to weight. If the mass is in kilograms, and the gravitational acceleration is in metres/second2 the result will be in Newtons, the SI unit for weight.
What will be the area of tank if length 1500mm breadth1500mm height 2000mm and plate thickness 6mm given.?
So, inner volume = 1488 * 1488 * 1994 = 4415003136 cubic mm or 4.415003136 cubic metres
What do you mean by internal radius?
It's the radius of a circle or sphere WITH A SHELL(or Thickness); like if an Lid on a jar had a diameter of 11mm across on the outside (top of lid); and was ONE mm thick, then the inside radius would be 5. ie; 11mm outer diameter, minus (-) 1mm thickness (aka; or shell) equals (=) 10mm (inner) diameter; which is a 5mm radius.
the thickness of inner core?
1220 km thick
What is the radial thickness of the solid earth kilometers?
The inner core is approximately 1271 kilometers in radius and is composed of iron and nickel, the liquid outer core is 2270 kilometers radius, and the radius of the mantle, the thickest solid layer, is 2885 kilometers.
How you can find total radius if inner radius and outer radius is given?
You must use the relationship between the inner radius and the outer radius. The relationship could very well be different every time you run into a problem like this, and I can't answer the question this time because you haven't described any relationship between them.
How do you calculate internal volume of a truncated cone shaped pipe?
If the Smaller inner radius is r, Larger inner radius is R, and the Length of the pipe is L then Vol = 1/3*pi*L*(R2 + Rr + r2)
