A squared = 6x6 = 36 B squared = 8x8 = 64 Square root of 36+64 = 10
Given: a2 + b2 = c2 a = 6 and b = 8. We need to find the value of c. a = 6 implies a2 = 62 = (6*6) = 36. b = 8 implies b2 = 82 = (8*8) = 64. a2 + b2 = c2 implies 62 + 82 = c2 c2 = 36 + 64 c2 = 100 c2 = 102 c = 10
The therom is used to find right triangles. The fourmula is A squared plus B squared equals C squared. Right now draw a right triangle on a sheet of paper. The two strait lines label A and B then the slanted side C. C is called the hypotineus. Now make A 6 squared and B 9 squared. Then write the fourmula and fit in the numbers now find out what 6 and 9 squared are. After you will see that you will 36 for 6 squared and 81 for 9 squared, then add them together. You will get 117, C is the square root of 117 so that would become 10.816653 rounded. Then square it and you have your hypotineus, And you just did the pathagreon therom. :-)
8.48, 6 squared+6 squared= c squared
x=2
X=2
To find the area of a shape with 6-inch sides, we first need to determine the type of shape. Assuming it is a square, the formula for the area of a square is side length squared. Therefore, the area would be 6 inches squared, which equals 36 square inches.
To calculate 6 squared plus 8 squared, you first need to square each number individually. 6 squared is 6 x 6, which equals 36. 8 squared is 8 x 8, which equals 64. Adding these two results together, you get 36 + 64, which equals 100. So, 6 squared plus 8 squared is 100.
89
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
(-4,-6)
b = sqrt32 or 4 root 2
X squared = x+6 6+x=x squared X=6
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
4
The discriminant is 121.
The graph is a circle with a radius of 6, centered at the origin.
(x + 3)(x + 2)
6 squared plus 9 squared is equal to 117.