8.48, 6 squared+6 squared= c squared
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
A square with a side length of 6 inches has an area of 36 square inches.
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
72 divided by 2 is 36 so the area is 36 then a square is side squared so the length of the side is 6.
The area of a square of length m is m2 Accordingly, for a square of side length 6 length units = 62 square units. = 36 square units
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
4.2 m
12 * root 2
You can use trigonometry to find the solution. A diagonal divides a square into two triangles, known as "45-45-90" triangles (because of the measures of each angle). According to a law of the same name, the hypotenuse (side opposite of the 90o angle) has a length equal to the length of a leg (side opposite of a 45o angle) times the square root of two. So, since the hypotenuse is a diagonal, you will find that the length of each side of the square is 6 divided by the square root of 2. Find the square of this, and you have the total area: 18 square yards.
The diagonal = the square root of (6 squared + 8 squared) 6 squared+8squared = 100 the square root of 100 = 10 so the length of the diagonal is 10. The above used Pythagoras' theorem which says the square on the diagonal is equal to the sum of the squares on the other two sides.
The diagonal across a square is one of three legs in a triangle. To determine the length of a leg in a triangle a formula was developed by the ancient Greek mathematician Pythagoras. The "Pythagorean Theorum" [A sq + B sq = C sq]using the two known legs to a triangle [A and B] to determine the third. since the leg [C]. Since we are determining the diagonal across a square we already that [A=6 meters] and [B=6 meters]. So therefore the equation 6 squared [36] + 6 squared [36] = 8.484 squared [72]. So the answer to the diagonal distance across a 6 meter square is; 8.484 meters
The side length is 6. For a square A = s2 and s = sqrt (A)
The answer in 6.... draw an angular bisector from one of the angles to the centre of circle then draw a perpendicular from the centre of circle. Those to lines will form a triangle... use trigonometry and find the length of the perpendicular, which is also a radius... double the radius and u will get the diagonal for the square... using formula :- (Side)^2 + (Side)^2 = (Diagonal)^2, find the side of square and square the answer, which will give you your final answer
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
The side of the square is 6. The diagonal of the square is 6 sqrt(2).The diagonal of the square is also the diameter of the circle.The circumference of the circle = pi times the diameter = 6 pi sqrt(2) = 26.657 (rounded)
A square with a side length of 6 inches has an area of 36 square inches.
A square with a side length of 6 inches has an area of 36 square inches.