8.48, 6 squared+6 squared= c squared
To find the diagonal of a square, we can use the formula for the diagonal of a square, which is d = s√2, where d is the diagonal length and s is the side length of the square. Given that the area of the square is 36, we can find the side length by taking the square root of the area, which is √36 = 6. Substituting s = 6 into the formula, we get d = 6√2. Therefore, the diagonal of the square with an area of 36 is 6√2 units.
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
A square with a side length of 6 inches has an area of 36 square inches.
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
72 divided by 2 is 36 so the area is 36 then a square is side squared so the length of the side is 6.
To find the diagonal of a square, we can use the formula for the diagonal of a square, which is d = s√2, where d is the diagonal length and s is the side length of the square. Given that the area of the square is 36, we can find the side length by taking the square root of the area, which is √36 = 6. Substituting s = 6 into the formula, we get d = 6√2. Therefore, the diagonal of the square with an area of 36 is 6√2 units.
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
The moment of inertia of a square plate about its diagonal is ((1/6))ma^2, where (m) is the mass of the plate and (a) is the length of the side of the square.
4.2 m
12 * root 2
You can use trigonometry to find the solution. A diagonal divides a square into two triangles, known as "45-45-90" triangles (because of the measures of each angle). According to a law of the same name, the hypotenuse (side opposite of the 90o angle) has a length equal to the length of a leg (side opposite of a 45o angle) times the square root of two. So, since the hypotenuse is a diagonal, you will find that the length of each side of the square is 6 divided by the square root of 2. Find the square of this, and you have the total area: 18 square yards.
To find the side length of a square with an area of 36, you need to take the square root of the area. In this case, the square root of 36 is 6. Therefore, the side length of the square is 6 units.
The diagonal across a square is one of three legs in a triangle. To determine the length of a leg in a triangle a formula was developed by the ancient Greek mathematician Pythagoras. The "Pythagorean Theorum" [A sq + B sq = C sq]using the two known legs to a triangle [A and B] to determine the third. since the leg [C]. Since we are determining the diagonal across a square we already that [A=6 meters] and [B=6 meters]. So therefore the equation 6 squared [36] + 6 squared [36] = 8.484 squared [72]. So the answer to the diagonal distance across a 6 meter square is; 8.484 meters
The answer in 6.... draw an angular bisector from one of the angles to the centre of circle then draw a perpendicular from the centre of circle. Those to lines will form a triangle... use trigonometry and find the length of the perpendicular, which is also a radius... double the radius and u will get the diagonal for the square... using formula :- (Side)^2 + (Side)^2 = (Diagonal)^2, find the side of square and square the answer, which will give you your final answer
The side of the square is 6. The diagonal of the square is 6 sqrt(2).The diagonal of the square is also the diameter of the circle.The circumference of the circle = pi times the diameter = 6 pi sqrt(2) = 26.657 (rounded)
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
To find the diagonal of a rectangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal (d) is the hypotenuse, and the length (l) and width (w) are the other two sides. So, d^2 = l^2 + w^2. Plugging in the values, we get d^2 = 6^2 + 8^2 = 36 + 64 = 100. Therefore, the diagonal is the square root of 100, which is 10.