This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
Knowing the area doesn't tell the perimeter. There are an infinite number of different perimeters that can all enclose the same area. The shortest one is a circle. The next shortest is a square. From there, you can actually make the perimeter as large as you want, with no limit, while keeping the area constant. Examples: 30 cm by 40 cm . . . . area = 1,200 cm2 . . . perimeter = 140 cm 10 cm by 120 cm . . . area = 1,200 cm2 . . . perimeter = 260 cm 2 cm by 600 cm . . . . area = 1,200 cm2 . . . perimeter = 1,204 cm 1 cm by 1,200 cm. . . area = 1,200 cm2 . . . perimeter = 2,402 cm 1
10
1 * 11 = 11 cm2 2 * 10 = 20 cm2 3 * 9 = 27 cm2 4 * 8 = 32 cm2 5 * 7 = 35 cm2 6 * 6 = 36 cm2 7 * 5 = 35 cm2 8 * 4 = 32 cm2 9 * 3 = 27 cm2 10 * 2 = 20 cm2 11 * 1 = 11 cm2
rectangle with 10" length and 2x-4 width 60" area
A rectangle with sides of 1cm and 6cm has an area of 6 cm2 and a perimeter of 14 cm. A rectangle with sides of 2cm and 3cm has the same area but its perimeter is 10 cm.
What is a rectangle were the area is 10 and the perimeter
It can be infinitely large. Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
No. For example, a 4x1 rectangle will have an area of 4 and a perimeter of 10. A 2x2 rectangle will have the same area of 4, but a perimeter of 8.
Yes. For instance, the rectangle measuring 1 by 10 has a perimeter of 22 and an area of 10, whereas the rectangle measuring 4 by 4 has a perimeter of 16 and an area of 16.
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
Width of rectangle: 50/10 = 5 cm
yes it can; a rectangle 5 by 2 has perimeter 14 and area 10 for example; a rectangle 10 by 2 has perimeter 24 and area 20, both greater.
40 meters.
2
Knowing the area doesn't tell the perimeter. There are an infinite number of different perimeters that can all enclose the same area. The shortest one is a circle. The next shortest is a square. From there, you can actually make the perimeter as large as you want, with no limit, while keeping the area constant. Examples: 30 cm by 40 cm . . . . area = 1,200 cm2 . . . perimeter = 140 cm 10 cm by 120 cm . . . area = 1,200 cm2 . . . perimeter = 260 cm 2 cm by 600 cm . . . . area = 1,200 cm2 . . . perimeter = 1,204 cm 1 cm by 1,200 cm. . . area = 1,200 cm2 . . . perimeter = 2,402 cm 1
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)