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What values of x is the area of the rectangle greater than the perimeter?
5x> 4
What are all the dimensions of a rectangle if your perimeter is 36?
The length is x units and the width is 18-x units, for all values of x that are greater than 9 and less than 18 units.
Shape has 6 rectangle faces?
A shape with 6 rectangle faces is a rectangular prism. It is similar to a cube, but with different values for its length, width, and height.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
What about if they tell you the width and the area of the rectangle?
The area of a rectangle is calculated by the formula: A = lw (area = length times width). If you know any two of those values, you can insert those values in the formula and calculate the third one.
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
The perimeter of a rectangle is 72m the width of the rectangle is 16m what is the area of the rectangle?
To find the area of a rectangle, you need to know the formula: Area = length x width. Given that the perimeter is 72m and the width is 16m, we can calculate the length by using the formula for perimeter of a rectangle: Perimeter = 2(length + width). Substituting the values we have, 72 = 2(length + 16), which simplifies to length + 16 = 36. Therefore, the length of the rectangle is 20m. Finally, the area of the rectangle is 20m x 16m = 320 square meters.
the width of a rectangle is w centimeters. the length of this rectangle is three times its width. the perimeter of the rectangle is greater than 64 centimeters. give the inequality that represents all possible values of w?
Let's set up an inequality to represent all possible values of the width (w) of the rectangle given the information provided. The length of the rectangle is three times its width, so the length (L) can be expressed as L = 3w. The perimeter (P) of a rectangle is given by the formula: P = 2(L + w). The perimeter is greater than 64 centimeters, so we have P > 64. Now, substitute the expression for L from step 1 into the perimeter formula from step 2: P = 2(3w + w) Simplify the expression inside the parentheses: P = 2(4w) P = 8w Now, we have the perimeter in terms of the width: P = 8w. We already know that P > 64, so we can write the inequality: 8w > 64 To isolate w, divide both sides of the inequality by 8: w > 64 / 8 w > 8 So, the inequality representing all possible values of the width (w) is: w > 8 This means that the width of the rectangle must be greater than 8 centimeters for the perimeter to be greater than 64 centimeters.
The area of a rectangle is 243 cm2 The length is three times greater than the width What are the dimensions?
Let the length be 3x and the width be x: 3x*x = 243 3x2 = 243 Divide both sides by 3: x2 = 81 Square root both sides: x = 9 Therefore: length = 27 cm and width = 9 cm
Is the area of a 28mm circle greater than a rectangle of 16mm x 35mm?
I assume 28mm is the radius of the circle. The area of such a circle would be (pi) x (28 squared) square mm The area of the rectangle 16mm width and 35mm length would be 16 x 35 square mm. Now can you evaluate the two values and figure out which is greater. I'm sure you can. Try it. Good luck!
Does the length and width have to be the same for an area?
They don't have to have the same value but they have to be in the same measurement units if, for example, you are multiplying the values to find the area of a rectangle.
The peremiter of a rectangle is 234 in the length exceeds the width by 39 inches find the length and width?
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
