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If two chords intersect inside a circle, the acute angle they form is one half of the sum of the arcs intercepted by its sides and by the vertical angle SO... The acute angle will be one half the sum of the two arcs. So it is 1/2(42+94)=68 degrees.

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Q: Chords ab and CD of circle o intersect inside the circle find the measure of the acute angle formed if arc ac is 42 and arc db is 94?
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