Assuming the measure of the arc refers to the angle at the centre of the circle, the answer is 180 - 150 = 30 degrees.
The angle between the two tangents is 20 degrees.
100 degrees
63o. Join the points where the tangents touch the circle to its centre to form a quadrilateral (two meeting tangents and two radii). These angles are both 90o, summing to 180o. Thus the other two angles - the one at the centre of the circle and the one where the tangents meet - sum to 360o - 180o = 180o (they are supplementary). The centre angle is given as 117o (the minor arc), so the angle where the tangents met is 180o - 117o = 63o.
To measure the point at which two tangents intersect each other, find an equation for each tangent line and compute the intersection. The tangent is the slope of a curve at a point. Knowing that slope and the coordinates of that point, you can determine the equation of the tangent line using one of the forms of a line such as point-slope, point-point, point-intercept, etc. Do the same for the other tangent. Solve the two equations as a system of two equations in two unknowns and you will have the point of intersection.
A pair of lines that intersect each other perfectly form 90 degree angles are perpendicular. Anything else is just intersecting lines
The angle between the two tangents is 20 degrees.
100 degrees
-- The major arc = 230 degrees-- The minor arc ... the arc between the tangents ... is (360 - 230) = 130 degrees.-- The line from the vertex of the angle to the center of the circle bisects the arc,so the angle between that line and the radius to each tangent is 65 degrees.-- The radius to each tangent is perpendicular to the tangent. So the radius, the tangent,and the line from the vertex to the center of the circle is a right triangle.-- In the right triangle, there's 90 degrees where the radius meets the tangent, and65 degrees at the center of the circle. That leaves 25 degrees for the angle at thevertex.-- With another 25 degrees for the right triangle formed by the other tangent,the total angle formed by the two tangents is 50 degrees.
63o. Join the points where the tangents touch the circle to its centre to form a quadrilateral (two meeting tangents and two radii). These angles are both 90o, summing to 180o. Thus the other two angles - the one at the centre of the circle and the one where the tangents meet - sum to 360o - 180o = 180o (they are supplementary). The centre angle is given as 117o (the minor arc), so the angle where the tangents met is 180o - 117o = 63o.
10 degrees.
72 degrees 72 degrees
To measure the point at which two tangents intersect each other, find an equation for each tangent line and compute the intersection. The tangent is the slope of a curve at a point. Knowing that slope and the coordinates of that point, you can determine the equation of the tangent line using one of the forms of a line such as point-slope, point-point, point-intercept, etc. Do the same for the other tangent. Solve the two equations as a system of two equations in two unknowns and you will have the point of intersection.
A pair of lines that intersect each other perfectly form 90 degree angles are perpendicular. Anything else is just intersecting lines
72 degrees. Use the formula: 360/n(number of sides)
Vertically opposite angles are the angles that are formed when two lines intersect. When the lines cross, they create two pairs of opposite angles that are equal in measure. For example, if two lines intersect and form angles of 40 degrees and 140 degrees, the angles across from each other (the vertically opposite angles) will both be 40 degrees and 140 degrees, respectively. This property is a fundamental concept in geometry.
If it's a regular 5 sided pentagon then each exterior angle measures 72 degrees
This is not possible. The supplement of 130 degrees is 50, the external degree measure.360 divided by 50 doesn't equal a whole number.