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Diagonal of a square whose area is 36?

Updated: 4/28/2022
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15y ago

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The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.

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Q: Diagonal of a square whose area is 36?
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What is the length of the diagonal of a square with an area of 36?

Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49


What is the area of a square whose perimeter is 36 inches?

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What are the dimensions of a square with a perimeter of 36 and a area of 45?

A square can't have a perimeter of 36 and an area of 45. If a square's perimeter is 36,then its area is 81. If a square's area is 45, then its perimeter is about 26.83 . (rounded)A figure whose perimeter is 36 and whose area is 45 is not a square. It's a rectanglethat measures (3 by 15).


What is the diagonal of a square whose area is 36?

First you want to find the lengths of the square. The formula for area is b × h, but because it's a square (and the base is the same as the height), the area can be expressed as b2. So if b2 = 36, then √36 = b. Therefore, b = 6.If you draw the diagonal in the square and make a triangle, you can use the two sides you do know to figure out the third side of the triangle using the Pythagorean theorem.62 + 62 = c272 = c2√72 = cc ≈ 8.49


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