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Using Pythagoras:

diagonal² = side² + side² = 2 × side²

→ side² = diagonal² ÷ 2

area = side²

= diagonal² ÷ 2

→ diagonal² = 2 × area

→ diagonal = √(2 × area)

= √(2 × 36)

= 6√2

≈ 8.49

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Q: What is the length of the diagonal of a square with an area of 36?
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