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First you want to find the lengths of the square. The formula for area is b × h, but because it's a square (and the base is the same as the height), the area can be expressed as b2. So if b2 = 36, then √36 = b. Therefore, b = 6.
If you draw the diagonal in the square and make a triangle, you can use the two sides you do know to figure out the third side of the triangle using the Pythagorean theorem.
62 + 62 = c2
72 = c2
√72 = c
c ≈ 8.49
What else can I help you with?
Diagonal of a square whose area is 36?
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
What is the length of the diagonal of a square with an area of 36?
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
What is the diagonal measurement of 36 foot by 36 foot square?
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.
Find the diagonal of a square whose are is 36?
First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.
What is the area of a rectangle with a diagonal of 39 and a height of 15?
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
Diagonal of a square whose area is 36?
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
What is the length of the diagonal of a square with an area of 36?
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
What is the area of a square whose perimeter is 36 inches?
The area of a square whose perimeter is 36 inches is: 81 square inches.
What are the dimensions of a square with a perimeter of 36 and a area of 45?
A square can't have a perimeter of 36 and an area of 45. If a square's perimeter is 36,then its area is 81. If a square's area is 45, then its perimeter is about 26.83 . (rounded)A figure whose perimeter is 36 and whose area is 45 is not a square. It's a rectanglethat measures (3 by 15).
What is the diagonal measurement of 36 foot by 36 foot square?
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.
What is the area of a square whose perimeter is 24 inches?
36 square inches.
What is the area of a square whose perimeter is twenty four?
36 square units.
What is the perimeter of a square whose area is 81ft?
36 ft
What is the area of a square whose side measures 6 in?
A square with a side length of 6 inches has an area of 36 square inches.
Find the diagonal of a square whose are is 36?
First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.First, take the square root, to get the length of a side. Then (because of Pythagoras), multiply the length of the side by the square root of 2.
What is the area of a rectangle with a diagonal of 39 and a height of 15?
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
What is the area of a square whose sides are 6 feet long?
It is 36 feet. 36 sqare feet
