They are all 4 sided quadrilaterals
If vertices are at (7, 3) (4, -3) and (10, -3) then it is an isosceles triangle because by using the distance formula it has 2 equal sides of 3 times square root 5 and a 3rd side of 6.
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
A shape with 5 letters in its name is a square. It's like a box, but all sides are the same length. So, if you're looking for a shape that's simple, symmetrical, and sassy, a square is your go-to gal.
6 sq e
4 Equal Sides on (a) Square
This is not considered a "squashed square". This is considered a rhombus, a 4 sided parallelogram, with all four sides with equal lengths, and an area of d1d2/2, suits the Euler Characteristic just like a square F - E + V = 0 - 4 + 4 = 0, and is possibly a square if it has a single right angle.
square such in e=mc2 2 = square
4e-1 = 7 Multiply both sides by e: 4 = 7e Divide both sides by 7: 4/7 = e
ln(√x)=√(lnx) because √x = x^(1/2), ln(x^(1/2))=√(lnx) using a logarithmic property, we can say that .5(lnx)=√(lnx) now, pretend that lnx=y .5y=√y square both sides .25y^2=y subtract y from both sides .25y^2 -y=0 factor y(.25y - 1)=0 so either y=0 or .25y -1 =0 If .25y -1=0, then y=4 so lnx=0 or lnx=4 lnx cannot equal zero because lnx=0 means e^x=0 and that is impossible. Now, we are left with lnx=4 Isolate x by making both sides of the equation powers of e: e^(lnx)=e^4 x=e^4, which is approximately 54.6 Lastly, check this answer by plugging e^4 back into the original equation: ln(√(e^4))=√(ln(e^4)) ln(e^2)=√(4(lne)) 2lne=2√1 2(1)=2 2=2 There you go!
e+4-9=45 (write down the equation) e-5=45 (simplify 4-9) e=50 (add 5 to both sides) Answer: e=50.
The square root of 16 is 4 and 4 cubed is 16x4=64
2e - 12 = 7e + 8 Subtract 2e from both sides: - 12 = 5e + 8 Subtract 8 from both sides: -20 = 5e Divide both sides by 5: -4 = e That is, e = -4
4 e - 9 = 19 + 9 = + 9 Inverse of -9 --------------------- 4 e +0 = 38 -9+9 cancels ----- ------- 4 4 Divide 4 to both sides ---------------------- e = 9.5 OR 9 R2
Answer: 10 sidesInterior angle = (180 * (number_of_sides - 2)) / number_of_sides Interior angle = 180 * (10-2) / 10 = 180 * 8 / 10 = 144Exterior angle = 360 / number_of_sides = 360 / 10 = 36 degreesRatio (144:36 = 4:1)Definitions:The exterior angle (e) is the angle created from the side and the imaginary line that would be if the adjacent side were to be extended beyond the vertices. The interior angle (i) plus the exterior angle (e) add up to 180 degrees, so i + e = 180. In a normal polygon, the sum of the exterior angle of all vertices adds up to 360 degrees; the sides do not overlap or cross. In a regular polygon each external angle is the same, and will divide evenly into 360 degrees to give the number of sides (n): 360 / e = n.Proof:Given that the ratio of the two angles is 4 to 1: i = 4e. Now substitute: i + e = 180; 4e + e = 5e = 180.e = 180 / 5 = 36 degrees.i = 180 - e = 144 degrees.360/e = 360/36 = 10 sides.The interior angle of a regular normal polygon of n sides is: i = (n-2)*180/n.For n=10: i = (10-2)*180/10 = 8*18 = 144 degrees, so it checks.Other i to e ratios:1 to 2: 3 sides: triangle (trigon) 2 to 2: 4 sides: tetrahedron (tetragon, square)3 to 2: 5 sides: pentahedron (pentagon)4 to 2: 6 sides: hexahedron (hexagon)5 to 2: 7 sides: heptahedron6 to 2: 8 sides: octahedron (octagon)7 to 2: 9 sides: enneahedron (nonogon)8 to 2: 10 sides: decahedron (decagon)
Vertices: E (-2, -1); F (-4, 3); G (1, 5); and H (3, 1).Plot these points in a coordinate system and connect them. The quadrilateral EFGH is formed.The slope of the line where the side EF lies is -2.[(3 - -1)/(-4 - -2)] = 4/-2 = -2The slope of the line where the side HG lies is -2.[(5 - 1)/(1 - 3)] = 4/-2 = -2Thus the opposite sides EF and HG of the quadrilateral EFGH are parallel.The slope of the line where the side EH lies is 2/5.[(1 - -1)/(3 - -2)] = 2/5The slope of the line where the side FG lies is 2/5.[(5 - 3)/(1 - -4)] = 2/5Thus the opposite sides EH and FG of the quadrilateral EFGH are parallel.Since any of the slopes is not a negative reciprocal of the others, then the two adjacent sides are not perpendicular. And if we look at the diagram, we clearly see that this quadrilateral can be a parallelogram.The length of the side EF is square root of 20.Square root of [(5 - 1)^2 + (1 - 3)^2] = Square root of [4^2 + (-2)^2] = Square root of 20.The length of the side HG is square root of 20.Square root of [(3 - -1)^2 + (-4 - -2)^2] = Square root of [4^2 + (-2)^2] = Square root of 20.Thus, the opposite sides EF and HG of the quadrilateral EFGH are congruent.Two other parallel sides, EH and FG, must be congruent also, since they intersect two other parallel lines (their length is equal to square root of 29).So we verified that the quadrilateral EFGH is a parallelogram.
a square number is a number times itself. Ex. 4 x4 = 16 16 is a square number.