Yes they do,because if both diagonal lines cross over and perform a cross is were the point in the middle meets.
no
Each diagonal of a rhombus would never bisect a pair of opposite angles, but the diagonals are perpendicular to each other
The diagonals of a rhombus are perpendicular. A rhombus is a special kind of parallelogram. It has the characteristics of a parallelogram (both pairs of opposite sides parallel, opposite sides are congruent, opposite angles are congruent, diagonals bisect each other.) It also has special characteristics. It has four congruent sides. So it looks like a lopsided or squished square. Its diagonals are perpendicular. Another property: each diagonal bisects two angles of the rhombus.
A rhombus is never a kite.A rhombus is a parallelogram with all its sides equal in length. Opposite angles are therefore equal and the rhombus is symmetrical about each of its diagonals.A kite is a quadrilateral having two pairs of adjacent sides equal in length. Only one pair of opposite angles is equal and the kite is symmetrical about the line that bisects the unequal opposite angles. A kite does not have any parallel sides.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
no
isn't it a rhombus ? the ones that are like a slanted square ? because there are no right angles but each diagonal bisects the corners.
Yes. In a rhombus (and in a square), the opposite angles that each diagonal connects are bisected by the diagonal.
The diagonals of a rhombus are perpendicular and intersect each other at right angles which is 90 degrees
One diagonal of a rhombus is larger than the other diagonal but both diagonals intercept each other at right angles.
Each diagonal of a rhombus would never bisect a pair of opposite angles, but the diagonals are perpendicular to each other
The diagonals are perpendicular to one another. The shorter diagonal is bisected by the longer diagonal. The kite is symmetrical about the longer diagonal. The longer diagonal bisects the angles at each end of the diagonal.
The diagonals of a rhombus are perpendicular. A rhombus is a special kind of parallelogram. It has the characteristics of a parallelogram (both pairs of opposite sides parallel, opposite sides are congruent, opposite angles are congruent, diagonals bisect each other.) It also has special characteristics. It has four congruent sides. So it looks like a lopsided or squished square. Its diagonals are perpendicular. Another property: each diagonal bisects two angles of the rhombus.
No, they do not. Only the longer diagonal bisects the shorter diagonal.
A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
The diagonals will cross each other half way at right angles.
If the diagonals of a parallelogram bisect its angles, then the parallelogram is a rhombus. In a rhombus, all sides are equal, and the diagonals not only bisect each other but also the angles at each vertex. This property distinguishes rhombuses from other types of parallelograms, such as rectangles and general parallelograms, where the diagonals do not necessarily bisect the angles. Thus, the statement implies a specific type of parallelogram.