A quadrilateral whose diagonals bisect each other at right angles is a rhombus. each other at right angles at M. So AB = AD and by the first test above ABCD is a rhombus. 'If the diagonals of a parallelogram are perpendicular, then it is a rhombus
Quadrilaterals do not bisect each other. They could in special cases. In parallelograms (types of quadrilaterals), the diagonals bisect each other.
No, they do not. Only the longer diagonal bisects the shorter diagonal.
A parallelogram a rectangle a square and a rhombus
Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal.
It has two diagonals, and they are perpendicular to each other.
Not necessarily.
Quadrilaterals do not bisect each other. They could in special cases. In parallelograms (types of quadrilaterals), the diagonals bisect each other.
Yes and the diagonals are not equal in length
squares
rhombus and a square
Parallelograms.
Square, rhombus and a kite have diagonals that bisect each other at 90 degrees
Square, rhombus and a kite
Arrow head
A square, a rhombus and a kite have diagonals that intersect each other at 90 degrees.
No, they do not. Only the longer diagonal bisects the shorter diagonal.
A square has two diagonals that bisect each other at 90 degrees