The midpoint of the line segment from ( 3, 7 ) to ( 8, 2 ) is at ( 5.5, 4.5 )
If you mean points of (-1, 5) and (6, -3) then the midpoint is (2.5, 1)
-1 + -2 = -3-3/2 = -1.54 + -9 = -5-5/2 = -2.5So the midpoint = (-11/2, -21/2)
The midpoint is at (3, 4)
Points: (-6, -3) and (9, -7) Midpoint: (1.5, -5)
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
If you mean points of (-3, -2) and (6, 2) then the midpoint is at (1.5, -3)
If you mean points of (-1, 2) and (7, 3) as on the Cartesian plane then the midpoint is at (3, 2.5)
If you mean points of (2, 3) and (-3, 2) then the midpoint is at (-0.5, 2.5)
To determine how many line segments have the midpoint (2, -3), you can consider that any two points on a coordinate plane that average to this midpoint will create a segment with that midpoint. There are infinitely many pairs of points that can achieve this, as you can choose various points (x1, y1) and (x2, y2) such that (x1 + x2)/2 = 2 and (y1 + y2)/2 = -3. Thus, there are infinitely many segments with the midpoint (2, -3).
If you mean points of (-2, 3) and (10, 3) then the midpoint is (4, 3)
Points:(4, 3) and (10, -5) Midpoint: (4+10)/2, (3-5)/2 = (7, -1)
The midpoint is (2,3)
Points: (-1, -9) and (4, -2) Midpoint: (3/2, -11/2)
Points: (-2, 6) and (4, 3) Midpoint: (1, 4.5)
To find the midpoint between the points (1, -7) and (-5, -3), you can use the midpoint formula, which is ((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})). Plugging in the coordinates, you get ((\frac{1 + (-5)}{2}, \frac{-7 + (-3)}{2})), which simplifies to ((-2, -5)). Therefore, the midpoint is (-2, -5).
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)
Points: (-12, -3) and (3, -8) Midpoint: (-9/2, -11/2) or as (-4.5, -5.5)