19 in
Perimeter = 2*(4ft 10in+6ft 4in) = 22ft 4in
4+4+6+5 = 19 inches is the perimeter
2(3+4) = 14 inches
5ft 4in
4 + 7 x 2 = 22 inches
6*(5ft 4 in) = 6*5ft + 6*4in = 30 ft + 24 in = 30 ft + 2 ft = 32 ft.
C = 25.13 inches.
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
it is not 4in it is 1/4in long
4in is less than 1 ft so 4in is a fraction of a foot 4/12 = 1/3 4in = 1/3ft = .33 ft
It depends on the shape of the area. Four sides of a quadrilateral - if that is what the given measurements are - do not determine a unique shape.
64in.