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Find the quadratic sequences nth term for these 4 sequences which are separated by the letter i iii 7 10 15 22 21 42 iii 2 9 18 29 42 57 iii 4 15 32 55 85 119 iii 5 12 27 50 81 120?
Wiki User
∙ 10y ago
Check if the given sequences are quadratic sequences.
7 10 15 22 21 42
The first difference: 3 5 7 1 21.
The second difference: 2 2 6 20.
Since the second difference is not constant, then the given sequence is not a quadratic sequence.
2 9 18 29 42 57
The first difference: 7, 9, 11, 13, 15.
The second difference: 2 2 2 2.
Since the second difference is constant, then the given sequence is a quadratic sequence. Therefore, contains a n2 term.
Let n = 1, 2, 3, 4, 5, 6, ...
Now, let's refer the n2 terms as, 1, 4, 9, 16, 25, 36.
As you see, the terms of the given sequence and n2 terms differ by 1, 5, 9, 13, 17, 21 which is an arithmetic sequence,say {an} with a common difference d = 4 and the first term a = 1. Thus, the nth term formula for this arithmetic sequence is
an = a + (n - 1)d = 1 + 4(n - 1) = 4n - 3.
Therefore, we can find any nth term of the given sequence by using the formula,
nth term = n2 + 4n - 3 (check, for n = 1, 2, 3, 4, 5, 6, ... and you'll obtain the given sequence)
4 15 32 55 85 119
The first difference: 11, 17, 23, 30, 34.
The second difference: 6 6 7 4.
Since the second difference is not constant, then the given sequence is not a quadratic sequence.
5 12 27 50 81 120
The first difference: 7, 15, 23, 31, 39.
The second difference: 8 8 8 8.
Since the second difference is constant, then the given sequence is a quadratic sequence.
I tried to refer the square terms of sequences such as n2, 2n2, 3n2, but they didn't work, because when I subtracted their terms from the terms of the original sequence I couldn't find a common difference among the terms of those resulted sequences. But, 4n2 works. Let n = 1, 2, 3, 4, 5, 6, ...
Now, let's refer the 4n2 terms as, 4, 16, 36, 64, 100, 144.
As you see, the terms of the given sequence and 4n2 terms differ by 1, -4, -9, -14, -19, -24 which is an arithmetic sequence, say {an} with a common difference d = -5 and the first term a = 1. Thus, the nth term formula for this arithmetic sequence is
an = a + (n - 1)d = 1 -5(n - 1) = -5n + 6.
Therefore, we can find any nth term of the given sequence by using the formula,
nth term = 4n2 - 5n + 6 (check, for n = 1, 2, 3, 4, 5, 6, ... and you'll obtain the
given sequence)
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∙ 10y ago
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