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look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)

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Q: How do you find the vertex from a quadratic equation in standard form?
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Write an algorithm to find the root of quadratic equation?

Write an algorithm to find the root of quadratic equation


The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?

In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.


How do you graph a quadratic equation?

A quadratic equation is an equation with the form: y=Ax2+Bx+C The most important point when graphing a parabola (the shape formed by a quadratic) is the vertex. The vertex is the maximum or minimum of the parabola. The x value of the vertex is equal to -B/(2A). Once you have the x value, just plug it back into the original equation to get the corresponding y value. The resulting ordered pair is the location of the vertex. A parabola will be concave up (pointed downward) if A is +. It will be concave down (pointed upward) if A is -. It is often helpful to find the zeroes of a function when graphing. This can be done by factoring or using the quadratic formula. For every n units away from the vertex on the x-axis, the corresponding y value goes up (or down) by n2*A. Parabolas are symetrical along the vertex, which means that if one point is n units from the vertex, the point -n units from the vertex has the same y value. As an example take the following quadratic: 2x2-8x+3 A=2, B=-8, and C=3 The x value of the vertex is -B/2A=-(-8)/(2*2)=2 By plugging 2 into the original equation we get that the vertex is at (2,-5) 3 units to the right (x=5) has a y value of -5+32*2=13. This means that 3 units to the left (x=-1) has the same y value (-1,13). If you need a clearer explanation, ask a math teacher.


How do you find maximum height when working with quadratic equations?

In a quadratic equation, the vertex (which will be the maximum value of a negative quadratic and the minimum value of a positive quadratic) is in the exact center of any two x values whose corresponding y values are equal. So, you'd start by solving for x, given any y value in the function's range. Then, you'd solve for y where x equals the middle value of the two x's given in the previous. For example:y = x24 = x2x = 2, -2y = (0)2y = 0Which is, indeed, the vertex of y = x2


How do you find the vertex and graph?

y = - x2 +6x - 5.5

Related questions

How would you use intercepts to find the vertex in a quadratic equation with two x intercepts?

The vertex must be half way between the two x intercepts


How do you find the x value of the vertex of a quadratic equation?

It depends on the level of your mathematical knowledge. One way is to differentiate the quadratic equation and find the value of x for which the derivative is 0. The advantage of this method is that it works for turning points of polynomials of all degrees. The disadvantage is that you need to know differentiation. For a quadratic, an alternative, and simpler way is to write the equation in the form: y = ax2 + bx + c Then the x value of the vertex is -b/2a


Write an algorithm to find the root of quadratic equation?

Write an algorithm to find the root of quadratic equation


The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?

In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.


What is the difference between quadratic formula and quadratic equation?

There are an infinite number of different quadratic equations. The quadratic formula is a single formula that can be used to find the pair of solutions to every quadratic equation.


Does quadratic equation relate to science?

No, the quadratic equation, is mainly used in math to find solutions to quadratic expressions. It is not related to science in any way.


Why do mathmaticians use the quadratic formula?

To find the roots (solutions) of a quadratic equation.


How can you find the complex solutions of any quadratic equation?

I suggest you use the quadratic formula.


How do you know if a quadratic equation will have one two or no solutions How do you find a quadratic equation if you are only given the solution Is it possible to have different quadratic equation?

Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .


How you find the solution of a quadratic equation by graphing its quadratic equation?

When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.


How do you graph a quadratic equation?

A quadratic equation is an equation with the form: y=Ax2+Bx+C The most important point when graphing a parabola (the shape formed by a quadratic) is the vertex. The vertex is the maximum or minimum of the parabola. The x value of the vertex is equal to -B/(2A). Once you have the x value, just plug it back into the original equation to get the corresponding y value. The resulting ordered pair is the location of the vertex. A parabola will be concave up (pointed downward) if A is +. It will be concave down (pointed upward) if A is -. It is often helpful to find the zeroes of a function when graphing. This can be done by factoring or using the quadratic formula. For every n units away from the vertex on the x-axis, the corresponding y value goes up (or down) by n2*A. Parabolas are symetrical along the vertex, which means that if one point is n units from the vertex, the point -n units from the vertex has the same y value. As an example take the following quadratic: 2x2-8x+3 A=2, B=-8, and C=3 The x value of the vertex is -B/2A=-(-8)/(2*2)=2 By plugging 2 into the original equation we get that the vertex is at (2,-5) 3 units to the right (x=5) has a y value of -5+32*2=13. This means that 3 units to the left (x=-1) has the same y value (-1,13). If you need a clearer explanation, ask a math teacher.


What statements must be true of an equation before you can use the quadratic formula to find the solutions?

That the discriminant of the quadratic equation must be greater or equal to zero for it to have solutions. If the discriminant is less than zero then the quadratic equation will have no solutions.