what is the slope of the line containing points (5-,-2) and (-5,3)? 2
Points: (6, 4) and (6, 8)Slope: 0 because it is a vertical straight line that is parallel to the y axis
The slope, m, of a line given 2 points is: (y2 - y1) / (x2 - x1). m = (-6 - (-9)) /(3-(-4)) or 3/7. Therefore parallel line slope is 3/7.
The line contains the points (3,6) and (-2,0). The slope of a line is equal to (y2-y1)/(x2-x1). In this case, the slope is (0-6)/(-2-3), which is (-6)/(-5), which is 6/5 or 1.2.
Since the line is horizontal, the slope is zero.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
The slope for these two points is undefined, or straight up.
The Slope of a line containing the points (2,2) and (4,2) is Y=0
Points: (-3, -3) and (4, -3) Slope: (-3--3)/(-3-4) = 0
Points: (2, 6) and (-3, -4) Slope: 2
Points: (2, 6) and (-3, -4) Slope: 2
If you mean points of (3, 4) and (-6, 10) then the slope is -2/3
Zero
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
Points: (6, -4) and (3, 4) Slope: -8/3
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
Points: (6, 4) and (6, 8)Slope: 0 because it is a vertical straight line that is parallel to the y axis