what is the slope of the line containing points (5-,-2) and (-5,3)?
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Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25
Write an algorithm to find the root of quadratic equation