what is the slope of the line containing points (5-,-2) and (-5,3)?
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Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
First find the slope and then use the fact that y = mx+c where m is the slope and c is the intercept on the y axis to find the equation. Slope: -4 - -3 over -1 - -7 = -1/6 Equation: y = -1/6x -25/6 or 6y = -x -25
Write an algorithm to find the root of quadratic equation
You solve an equation containing y.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
The measures of two angles in a triangle are shown in the diagram. Which equation can be used to find the value of x?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
To find the equation of a line given two points, we first need the coordinates of both points. Assuming the points are (-4, 3) and (7, 5), we calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 3}{7 - (-4)} = \frac{2}{11} ). Next, using the point-slope form ( y - y_1 = m(x - x_1) ), we can take one of the points, say (-4, 3), to find the equation: ( y - 3 = \frac{2}{11}(x + 4) ). Simplifying this gives the equation of the line.
To find the equation of the line containing the points (-5, 11) and (3, 4), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{4 - 11}{3 - (-5)} = \frac{-7}{8} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with point (-5, 11), the equation becomes ( y - 11 = -\frac{7}{8}(x + 5) ). Simplifying, the equation of the line is ( y = -\frac{7}{8}x + \frac{33}{8} ).
An equation crosses the horizontal axis at points where the output value (usually represented by (y)) is zero. These points are known as the roots or x-intercepts of the equation. To find these points, you set the equation equal to zero and solve for the variable, typically represented as (x). Graphically, this represents the points where the graph of the equation intersects the x-axis.
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
The slope for these two points is undefined, or straight up.
To determine which points are on the line given by the equation ( y = 2x ), you can substitute the x-coordinate of each point into the equation and see if the resulting y-coordinate matches the point's y-coordinate. For example, if you have the point (1, 2), substituting ( x = 1 ) gives ( y = 2(1) = 2 ), so this point is on the line. Repeat this process for each point to find which ones satisfy the equation.
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how