Points: (6, 4) and (6, 8)
Slope: 0 because it is a vertical straight line that is parallel to the y axis
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
The slope, m, of a line given 2 points is: (y2 - y1) / (x2 - x1). m = (-6 - (-9)) /(3-(-4)) or 3/7. Therefore parallel line slope is 3/7.
Since the line is horizontal, the slope is zero.
Two points on a graphed line are (4, 7) and (3, 8). What is the slope of the line?
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
The Slope of a line containing the points (2,2) and (4,2) is Y=0
Points: (6, -4) and (3, 4) Slope: -8/3
Points: (2, 6) and (-3, -4) Slope: 2
Points: (2, 6) and (-3, -4) Slope: 2
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
If you mean points of: (-2, -4) and (4, 5) then the slope works out as 3/2
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
The slope for these two points is undefined, or straight up.
If you mean points of (3, 4) and (-6, 10) then the slope is -2/3
Points: (2, 7) and (4, 4) Slope: -3/2
Points: (-3, -3) and (4, -3) Slope: (-3--3)/(-3-4) = 0
The slope of a line that has the points 3, (-4), and has a slope of 2 is 2.