A=m*h m=(a+b)/2
Area = 1/2*(sum of the two bases)*height
Area of a trapezoid = 0.5*(sum of parallel sides)*height
The area of a trapezoid is one-half the product of the length of an altitude and the sum of the lengths of the bases: A=1/2(b1 + b2)
leanth times width
Area of a trapezoid = 0.5*(sum of parallel sides)*height
A=m*h m=(a+b)/2
Area = 1/2*(sum of the two bases)*height
The formula for finding the area of a trapezoid is:A = (1/2) (b1 + b2 ) h
Area = 1/2*(sum of parallel sides)*height and measured in square units
You are not finding the area you are finding the volume. The answers is 1232 cm3
Area of a trapezoid = 0.5*(sum of parallel sides)*height
It is the sum of its 4 sides
The formula for the area of a trapezoid is A = 1/2 (b1 + b2)/h where b1 is the upper base of the trapezoid , b2 is the lower base of the trapezoid and h is the height of the trapezoid. Since a triangle has only one base , replace either b1 or b2 with zero. Thus the area of a triangle is A = 1/2bh
Area of a trapezoid = 0.5*(sum of parallel sides)*height
They both use perpendicular height and are in square units. Area of a trapezoid = 0.5*(sum of parallel sides)*perpendicular height Area of a parallelogram = base*perpendicular height
from a pyramid