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How do you find area of triangle with base 9 feet 3 inches and altitude 5 feet 6 inches?
Also, we know that 1 foot = 12 inches.
Implies 3 inches = 0.25 feet and 6 inches = 0.5 feet.
9 feet 3 inches = 9 feet + 0.25 feet = 9.25 feet
5 feet 6 inches = 5 feet + 0.5 feet = 5.5 feet
Area = (1/2) * base * height.
Given: Base = 9 feet 3 inches = 9.25 feet.
Height = 5 feet 6 inches = 5.5 feet.
Area = (1/2) * 9.25 * 5.5
= (0.5) (9.25) (5.5)
= 25.4375 square feet.
What else can I help you with?
Area of a equilateral triangle?
Area = 0.5*base*altitude
What is the area of a parallelogram with a base of 20 inches and an altitude of 8 inches?
The area of a parallelogram with a base of 20 inches and an altitude of 8 inches is 160 square inches.
How do you find the area of an iscoseles triangle?
Half base x altitude...
The area of a triangle XYZ is 48 inches the base of the triangle is 8 inches what is the height in inches?
12 inches
What is the area of a triangle with a base of 8 inches and a height of 6 inches?
The formula for the area of a triangle is: (1/2)Base x Height So the triangle would have an area of (1/2)(8 inches)(6 inches) = 24 inches2
The altitude of a triangle is 5 inches less than its base. the area of the triangle is 42 square inches . find its base and altitude?
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
A triangle has an area of 144 sq inches and its base is 2 ft long What is the altitude of the triangle?
First convert the base to the same kind of units you have defined the area in (but linear); 24 inches. The area of a triangle is half of the base times the height .12 (half the base) times what is 144?12, the height (altitude) of the triangle is 12 inches (one foot).
What is the area of a triangle with a base of 10in and an altitude of 14in?
70 square inches
What is the area of a triangle that has a base of 6inches and an altitude of 8 inches?
Area = 0.5*6*8 = 24 square inches
What is the area of a triangle having a base of 16 inches and an altitude of 4 inches?
32 inches squared. 16 times 4 is 64, and divide by two since it is a triangle. You get 32 and it has to be inches squared because it is area.
What would the area of a triangle with a base of 20 in and a height of 5 in?
Area = 0.5*Base*Altitude = 0.5*20*5 = 50 square inches.
A rectangle and triangle have equal areas the length of the rectangle is 12 in and its width is 8 in if the base of the triangle is 32 in what is the length in inches of the altitude drawn to the base?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
What is the area of an equilateral triangle with a side of 20 inches?
Area = 1/2*altitude*base Area = 1/2*17.32050808*20 Area = 173.2050808 square inches The altitude or height was worked out by using Pythagoras' theorem.
What is the area of a triangle with base 16 cm and altitude to that base of 8 cm?
The area of triangle is : 64.0
What is the formula for area of a base and area of a triangle?
A base is normally a line and therefore has no area; the area of a triangle is half of base x altitude.
Area of a equilateral triangle?
Area = 0.5*base*altitude
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches altitude drwn to ba?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
