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A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
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A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
A rectangle and triangle have equal areas. The rectangle is 12 inches long and 8 inches wide. If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?
The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6
Is the altitude of an equilateral triangle equal to a side length?
No. The altitude is smaller.
What is the relationship between the area of a triangle and a rectangle?
The relationship between the area of a triangle and a rectangle is a Triangle is base times height divided by 2. Area of a rectangle is length times height.
What is the perimeter of a triangle with sides 11 inches 5 inches and 13 inches?
The perimeter is 11 + 5 + 13 = 29 inches.
A rectangle and triangle have equal areas the length of the rectangle is 12 in and its width is 8 in if the base of the triangle is 32 in what is the length in inches of the altitude drawn to the base?
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitude dra?
6
The length of the rectangle is 12 inches and its width is 8 inches if the base of a triangle is 32 inches what is the length in inches of the altitude drawn to the base?
6
A rectangle and triangle have equal areas - the rectangle's length is 12 inches and its width is 8 inches so if the base of the triangle is 32 inches what is the length in inches of the altitude drawn?
The rectangle has an area of 12 x 8 = 96 square inches. The triangle has an area of (1/2 * 32 * x). So, 16x = 96, therefore x = 6. The height of the triangle is 6 inches.
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the?
The formula for the area (R) of a rectangle is R = length x width = 12 x 8 = 96 sq in.The formula for the area (T) of a triangle is T = 1/2 base x altitude (a)(or vertical height) Then 96 = 1/2 x 32 x a : 96 = 16a : therefore a = 6 inches.Answer : The altitude of the triangle = 6 inches
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altitu?
6
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the alt?
6
A rectangle and triangle have equal areas. The rectangle is 12 inches long and 8 inches wide. If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?
The altitude will be 6 inches in length. The area of the rectangle is length (l) times width (w) or l x w = 12 x 8 = 96 The area of a triangle is 1/2 the base (b) times the height (h), or altitude, and, because the area of the triangle is equal to the area of the rectangle, both will have an area of 96. For the triangle, 1/2 b x h = 1/2 x 32 x h = 96, and 16 x h = 96, and h = 6
A rectangle and a triangle have equal areas The length of the rectangle is 12 inches and its width is 8 inches If the base of the triangle is 32 inches what is the length in inches of the altiitude dr?
6 inches
A rectangle and a triangle have equal areas If the rectangle has a length of 12 inches and a width of 8 inches and the base of the triangle is 32 inches what is the length of altitude drawn to base?
Area of the rectangle = (Length x Width) = (12 x 8) = 96Area of the triangle = 1/2 (Base x Altitude) = 1/2 (32 x Alt) = also 96 1/2 (32 x Alt) = 96 32 x Alt = 192 Alt = 192/32 = 6 inches
A rectangle and triangle have equal areas The rectangle is 12 inches long and 8 inches wide If the base of the triangle is 32 inches what is the length in inches of the altitude drawn to the base?
Area Rectangle = 12 * 8 = 96 sq. in.Area Triangle = 1/2 base * height -> 96 = 16 * height -> 96 / 16 = height = 6 in.
What is the length of a diagonal rectangle with a length of 9 inches and a width of 3 inches?
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
