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In spherical geometry we look at the globe as the sphere S^2. Any plane intersecting the sphere will create a great circle. Now if you take any point on the globe and reflect it across that plane, you have another point that is equidistant from the plane. The sets of all these points will be equidistant from the great circle.
What else can I help you with?
How do you find a point equidistant from three other points?
To find a point equidistant from three other points, construct perpendicular bisectors for two of the segments formed from three points. Note: this will be the center of the circle that has all three points on it's circumference. Three points, not in a straight line, form three pairs of points with each pair defining a different line. Take any pair of points and draw the perpendicular bisector of the line joining them. Repeat for one of the other pairs. These two perpendicular bisectors will meet at the point which is equidistant from all three points - the circumcenter of the triangle formed by the three points.
Set of all points equidistant from a given point?
Circle!
What is an equation of the locus of points equidistant from the points 4 1 and 10 1?
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
What is a point that is equidistant from all points on a circle?
The center of the circle. That's how the circle is defined. (The collection of all points on a plane equidistant from a fixed point. The fixed point is the center and the fixed distance is the radius.)
All the points equidistant to a given point would form?
A circle.
What is the three dimensional shape that all points are equidistant from the center?
On a sphere, all points on the surface are equidistant from the center.
Briefly explain the focus and directrix of a parabola?
the set of points equidistant from a fixed point
How many points are there that are equidistant points a and b and also 2in from the line passing through a and b?
To find the points that are equidistant from points A and B, you would first determine the perpendicular bisector of the line segment AB, which is a line that is equidistant from both points. For the points that are also 2 units from the line passing through A and B, there will be two lines parallel to the perpendicular bisector, each located 2 units away. Therefore, there are exactly two points that satisfy both conditions.
How do you find a point equidistant from three other points?
To find a point equidistant from three other points, construct perpendicular bisectors for two of the segments formed from three points. Note: this will be the center of the circle that has all three points on it's circumference. Three points, not in a straight line, form three pairs of points with each pair defining a different line. Take any pair of points and draw the perpendicular bisector of the line joining them. Repeat for one of the other pairs. These two perpendicular bisectors will meet at the point which is equidistant from all three points - the circumcenter of the triangle formed by the three points.
What is the set all points in a plane that are equidistant from two points is a?
J
Locus of points equidistant from a point?
circle
What is the set of all points in the plane equidistant from one point in the plane?
The set of all points in the plane equidistant from one point in the plane is named a parabola.
All the points on a plane that are equidistant from a single point?
All points on the circumference of a circle drawn on a plane are equidistant from the single point on the plane which is the center of the circle.
What is a locus of points equidistant from a point?
A locus of points is just the set of points satisfying a given condition. The locus of points equidistant from a point is a circle, since a circle is just a set of points which are all the same distance away from the center
What is the locus of points in a plane that are equidistant from points A and B in the plane?
a straight line ..
What do you call a set of points equidistant from a point?
A selection of some points on a circle.
How do you find the equal distance from each of your three points?
It is the circumcentre of the triangle formed by the three points. Draw the perpendicular bisectors of two of the lines joining the three points. They will meet at the point that is equidistant from the three points.
