Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],
and that's the equation.
The locus of points (or collection of all points) that are 10 centimeters from a given point would be a circle (of radius 10 cm) in two dimensions, and a sphere (of radius 10 cm) in three dimensions.
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
x2+y2+4x+6y-40 = 0 and x = 10+y Substitute the second equation into the first equation: (10+y)2+y2+4(10+y)+6y-40 = 0 2y2+30y+100 = 0 Divide all terms by 2: y2+15y+50 = 0 (y+10)(y+5) = 0 => y = -10 or y = -5 Substitute the above values into the second equation to find the points of intersection: Points of intersection are: (0, -10) and (5, -5)
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
If you mean: y=-5x+10 and the point (3, 10) then the parallel equation is y=-5x+25
The locus of points (or collection of all points) that are 10 centimeters from a given point would be a circle (of radius 10 cm) in two dimensions, and a sphere (of radius 10 cm) in three dimensions.
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
Points: (5, -1) and (10, -5) Slope: -4/5 Equation: 5y = -4x+15
The equation works out as: 5y = 2x or as y = 2/5x
If you mean points of: (10, -2) and (20, -12) then it is a straigh line equation in the form of y = -x+8
y = -1.125x + 2.25
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
Points: (-6, 0) and (0, -10) Slope: -5/3 Equation: y-0 = -5/3(x--6) => 3y = -5x-30 Equation: y--10 = -5/3(x-0) => 3y = -5x-30