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What is an equation of the locus of points equidistant from the points 4 1 and 10 1?
Wiki User
∙ 12y ago
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],
and that's the equation.
Wiki User
∙ 12y ago
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What is the locus of points that are 10 centimeters from a given point?
The locus of points (or collection of all points) that are 10 centimeters from a given point would be a circle (of radius 10 cm) in two dimensions, and a sphere (of radius 10 cm) in three dimensions.
What is equation point slope form contains the points 8 10 and -4 2?
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
Where are the points of intersection on the curve and line of x squared plus y squared plus 4x plus 6y minus 40 equals 0 and x equals 10 plus y?
x2+y2+4x+6y-40 = 0 and x = 10+y Substitute the second equation into the first equation: (10+y)2+y2+4(10+y)+6y-40 = 0 2y2+30y+100 = 0 Divide all terms by 2: y2+15y+50 = 0 (y+10)(y+5) = 0 => y = -10 or y = -5 Substitute the above values into the second equation to find the points of intersection: Points of intersection are: (0, -10) and (5, -5)
What is the distance between the points -6-10 and 25?
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
Find the equation of a line parallel to y - 5x 10 that passes through the point (3 10). (answer in slope-intercept form)?
If you mean: y=-5x+10 and the point (3, 10) then the parallel equation is y=-5x+25
What is the locus of points that are 10 centimeters from a given point?
The locus of points (or collection of all points) that are 10 centimeters from a given point would be a circle (of radius 10 cm) in two dimensions, and a sphere (of radius 10 cm) in three dimensions.
What is equation point slope form contains the points 8 10 and -4 2?
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
What is the equation of the line containing the points 5 2 10 4 and 15 6?
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
What is the answer for points (5-1) and (10-5)?
Points: (5, -1) and (10, -5) Slope: -4/5 Equation: 5y = -4x+15
What is the equation of the line containing the points (5 2) (10 4) and (15 6)?
The equation works out as: 5y = 2x or as y = 2/5x
What is the function of the line that contains the points (10-2) and (20-12)?
If you mean points of: (10, -2) and (20, -12) then it is a straigh line equation in the form of y = -x+8
What is the equation of the line passing through the points 2 0 and 10 -9?
y = -1.125x + 2.25
Is 11 closer to 10 or 12?
Neither. It is equidistant.
What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What is the equation for a line that passes through the points (-50) and (109)?
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the equation of the line whose coordinates are at 2 3 and 11 13?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9x = 10x+7
