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What is the locus of points equidistant from two points A and B that are 8 meters apart?
It is the perpendicular bisector of AB, the line joining the two points.
Given two points A and B in the three dimensional space what is the set of points equidistant from A and B?
A plane is the set of all points in 3-D space equidistant from two points, A and B. If it will help to see it, the set of all points in a plane that are equidistant from points A and B in the plane will be a line. Extend that thinking off the plane and you'll have another plane perpendicular to the original plane, the one with A and B in it. And the question specified that A and B were in 3-D space. Another way to look at is to look at a line segment between A and B. Find the midpoint of that line segment, and then draw a plane perpendicular to the line segment, specifying that that plane also includes the midpoint of the line segment AB. Same thing. The set of all points that make up that plane will be equidistant from A and B. At the risk of running it into the ground, given a line segment AB, if the line segment is bisected by a plane perpendicular to the line segment, it (the plane) will contain the set of all points equidistant from A and B.
Describe the locus of points that are 9 cm from point B?
a circle 9 cm from point b I was co fused by this but you just do a diagram and write this
How many lines can you draw though points A and B?
Infinitely many. But only one straight line in a plane.
Three points A B and C which lie on a level plane B is 7 km from A on a bearing of 030 C is 5 km from B on a bearing of 280 what is the distance of AC?
Approx 7.075 km.
