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What is the locus of points equidistant from two points A and B that are 8 meters apart?
It is the perpendicular bisector of AB, the line joining the two points.
Given two points A and B in the three dimensional space what is the set of points equidistant from A and B?
A plane is the set of all points in 3-D space equidistant from two points, A and B. If it will help to see it, the set of all points in a plane that are equidistant from points A and B in the plane will be a line. Extend that thinking off the plane and you'll have another plane perpendicular to the original plane, the one with A and B in it. And the question specified that A and B were in 3-D space. Another way to look at is to look at a line segment between A and B. Find the midpoint of that line segment, and then draw a plane perpendicular to the line segment, specifying that that plane also includes the midpoint of the line segment AB. Same thing. The set of all points that make up that plane will be equidistant from A and B. At the risk of running it into the ground, given a line segment AB, if the line segment is bisected by a plane perpendicular to the line segment, it (the plane) will contain the set of all points equidistant from A and B.
Describe the locus of points that are 9 cm from point B?
a circle 9 cm from point b I was co fused by this but you just do a diagram and write this
How many lines can you draw though points A and B?
Infinitely many. But only one straight line in a plane.
Three points A B and C which lie on a level plane B is 7 km from A on a bearing of 030 C is 5 km from B on a bearing of 280 what is the distance of AC?
Approx 7.075 km.
What is the locus of points equidistant from two points A and B that are 8 meters apart?
It is the perpendicular bisector of AB, the line joining the two points.
Given two points A and B in the three dimensional space what is the set of points equidistant from A and B?
A plane is the set of all points in 3-D space equidistant from two points, A and B. If it will help to see it, the set of all points in a plane that are equidistant from points A and B in the plane will be a line. Extend that thinking off the plane and you'll have another plane perpendicular to the original plane, the one with A and B in it. And the question specified that A and B were in 3-D space. Another way to look at is to look at a line segment between A and B. Find the midpoint of that line segment, and then draw a plane perpendicular to the line segment, specifying that that plane also includes the midpoint of the line segment AB. Same thing. The set of all points that make up that plane will be equidistant from A and B. At the risk of running it into the ground, given a line segment AB, if the line segment is bisected by a plane perpendicular to the line segment, it (the plane) will contain the set of all points equidistant from A and B.
Points A and B are 6 units apart How many points are equidistant fomr A and B and 2 units from A?
None. If a point is 2 units from 'A' and equidistant from 'A' and 'B', then it also has to be2 units from 'B'.But the shortest distance between 'A' and 'B' is 6 units, and the point on that line that's equidistantfrom both of them is the point in the middle, which is 3 units from each.So a point equidistant from 'A' and 'B' must be 3 or more units from each one. 2 units won't do it.
Describe the locus of points that are 9 cm from point B?
a circle 9 cm from point b I was co fused by this but you just do a diagram and write this
What points are in the first quadrant of the xy-plane?
All ordered pairs, (a,b) such that a > 0 and b > 0
How many planes can be determined by A B and C?
If points A, B, and C are not on the same line, they determine a single plane.
The locus of A B O genes on chromosomes?
It is 8..
A cone is a solid with base that is a point not in the same plane as the base and all the points between them?
B. disc
How can you construct a parallelogram?
Use two line segments (line A and line B) with all points on line A equidistant from all points on line B; in otherwords, use 2 parallel lines. Choose two points on line A (points a and b). Now choose 2 points on line B (x and y) so that the distance of line ab equals the distance of line xy. Connect points a and y with a line segment ab and points b and z with a line segment bz. In simpler words, take two parallel line segments of equal length, and connect their endpoints with two other line segments.
If A and B are two points in the plane the perpendicular bisector of line segment AB is the set of all points equidistant from A and B?
Let us consider a line l such that it is the perpendicular bisector of line segment AB and the line intersects at point C.Let us take any point on line l(say, D). Join A to D and B to D.Now we have two triangles ACD and BCD.Now, in triangles ACD & BCD, we haveCD = CD (Common side)�ACD = �BCD (Right angle)AC = BC (Since l bisects AB)According to Side-Angle-Side criteria: Both triangles are congruent.Since both triangles are congruent, therefore AD = BD.So, l is the set of all points equidistant from A & B.Hence proved.
What are the values of a and b when y plus 4x equals 11 is the perpendicular bisector of the line joining a 2 to 6 b showing workings?
They must be equidistant from the point of bisection which is their midpoint and works out that a = -2 and b = 4 Sketching the equations on the Cartesian plane will also help you in determining their values
How many lines can you draw though points A and B?
Infinitely many. But only one straight line in a plane.
