This is a good question, and you need to know the quadratic formula
let A = area
b = width
h = height
P = perimeter
A = bh
b = A/h
P = 2b + 2h
P = 2A/h +2h = (2h^2 + 2A)/h
Ph = 2A + 2h^2
2h^2 - Ph + 2A = 0
use quadratic formula to solve:
h =( P +/- SQRT(P^2 -16A))/4
This gives both sides b and h using plus then minus the square root
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