The clever person might realize that, though an infinite number of rectangles can be created with a fixed perimeter, there is a maximum and minimum area that any rectangle formed under the constriction can have. And we can work with that. The minimum area will be "near" zero. (With an area "at" zero, the rectangle will collapse and/or disappear.) The rectangle with "maximumized" area for a fixed perimeter will be a square. Its side (designated by "s") will be one fourth of the perimeter (designated by "p"). If s = p/4 and we use the formula for finding the area (As) of a square substituing our "p/4" for the side length "s" we will get the equation: As = (p/4)2 Our rectangle(s) will all have an area (Ar) within this range: Zero is less than Ar which is less than or equal to (p/4)2 Though we couldn't come up with a precise answer, we came up with the next best thing with the information supplied.
area is length times width
To find the area of a rectangle, when you only know the perimeter, you can just just break the sides down into two pairs of lengths. For example; if the known perimeter is 100, you can call the two short sides, we'll call those the width, 10 (x2=20) and the two long sides, we'll call those length, 40 (x2=80) 20+80=100... Now you know all the lengths of the sides, so the area formula is L x W = area or 10 x 40 = 400. Any rectangle with a perimeter of 100 will have an area of 400, no matter what the lengths are and the process works for any rectangle, you just have to break the perimeter length down into two pairs of lengths.+++That starts off right but is NOT the full method.'You need to know the ratio between its length and breadth. Then apply that ratio to half of the perimeter to find the length and breadth.'Try it:L = 4, B= 6 so P = 20 but Area = 4 X 6 = 24 square units.L = 2, B = 8 so P = 20 again BUT Area now = 2 X 8 = 16 sq. units.For any given rectangle perimeter, there is an infinite number of possible areas.For a quadrilateral, Perimeter-only works only for the Square, for which A = [P/4]^2 = [(P^2)/16]
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The area of EVERY rectangle is the product of (length) times (width).Knowing that, you can now find the area of not only that particular rectangle,but also every rectangle you ever encounter for the rest of your life.Man, you are empowered !
To find area given perimeter, rename perimeter to circumference and solve with these formulas: Circumference = 2πr (or 2 * π * r) Area = πr^2 (or π * r * r) With these the area can be found from circumference(or perimeter) as follows: A = π(C / 2π)^2 Now, to find the perimeter given the area; We use A = πr^2 and rearrange then solve: r = √(A / π) So, the circumference would be 2πr = 2π√(A / π)
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
To find the area of a rectangle, you multiply the length by the width (one side by a different side) Or you could count how many centimeter squares make up the rectangle
you can not do that....that is what i guess but ask someone else i have never heard that before.
Length + width = half the perimeter, but more info eg area, is needed.
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 unit will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.+++To summarise, you can, IF you know the ratio as mentioned. Then apply that to half the perimeter to find the length and breadth.
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
There is no such thing as the area of the perimeter. A perimeter is a length and so has only 1 dimension. As such, its area is 0.
if the house is a square or rectangle then you need only measure two adjoining sides, you can them multiply these together to get the area, or add the two distances together and then times 2 for the perimeter
The area cannot be 15 feet since that is a measure of length, not area. In any case, information about the area cannot determine the perimeter; it can only put a lower limit on it. The perimeter can be anyhting from 15.49193 ft upwards. Consider the following rectangles, all with area = 15 square feet: a sqrt(15)*sqrt(15) rectangle will have a perimeter of 4*sqrt(15) = 15.49193 ft (approx). 1ft*15ft rectangle will have a perimeter of 32 feet 0.1ft*150ft rectangle: perimeter = 300.2 feet 0.01ft*1500ft rectangle: perimeter = 3000.02 ft 0.001ft*15000ft rectangle: perimeter = 30000.002 ft by now you should see that there is no upper limit to the perimeter.
If you are talking about a rectangle, you can't find the area from just the perimeter. With a perimeter of say 80 units, the sides could be 10 and 30, with an area of 300 square units. But the sides could also be 5 and 35, with an area of 175 square units. There are lots of other possibilities. If you are talking about a square, that's different. Each side is a quarter of the perimeter, so the area is a quarter of the perimeter multiplied by a quarter of the perimeter.
You can't: perimeter = 2 x (length + width), assuming you're talking about a rectangle.
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 until will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.