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The clever person might realize that, though an infinite number of rectangles can be created with a fixed perimeter, there is a maximum and minimum area that any rectangle formed under the constriction can have. And we can work with that. The minimum area will be "near" zero. (With an area "at" zero, the rectangle will collapse and/or disappear.) The rectangle with "maximumized" area for a fixed perimeter will be a square. Its side (designated by "s") will be one fourth of the perimeter (designated by "p"). If s = p/4 and we use the formula for finding the area (As) of a square substituing our "p/4" for the side length "s" we will get the equation: As = (p/4)2 Our rectangle(s) will all have an area (Ar) within this range: Zero is less than Ar which is less than or equal to (p/4)2 Though we couldn't come up with a precise answer, we came up with the next best thing with the information supplied.
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How do you find area and length of a rectangle if perimeter and breadth is given?
Well, isn't that just a happy little problem to solve! To find the area of a rectangle, you multiply the length by the breadth. And to find the length, you can use the formula: length = (perimeter - 2 * breadth) / 2. Just remember, there are no mistakes, only happy accidents in math!
How do you find the area of a parallelogram with only the perimeter?
area is length times width
How do you find the the area of the rectangle if perimeter is given?
To find the area of a rectangle, when you only know the perimeter, you can just just break the sides down into two pairs of lengths. For example; if the known perimeter is 100, you can call the two short sides, we'll call those the width, 10 (x2=20) and the two long sides, we'll call those length, 40 (x2=80) 20+80=100... Now you know all the lengths of the sides, so the area formula is L x W = area or 10 x 40 = 400. Any rectangle with a perimeter of 100 will have an area of 400, no matter what the lengths are and the process works for any rectangle, you just have to break the perimeter length down into two pairs of lengths.+++That starts off right but is NOT the full method.'You need to know the ratio between its length and breadth. Then apply that ratio to half of the perimeter to find the length and breadth.'Try it:L = 4, B= 6 so P = 20 but Area = 4 X 6 = 24 square units.L = 2, B = 8 so P = 20 again BUT Area now = 2 X 8 = 16 sq. units.For any given rectangle perimeter, there is an infinite number of possible areas.For a quadrilateral, Perimeter-only works only for the Square, for which A = [P/4]^2 = [(P^2)/16]
The number feared by Pythagoreans since it lies halfway between the only integers that can be both the perimeter and the area of the same rectangle?
17
How do you find the perimeter of mixed numbers?
you can only find the perimeter of shapes, honey, not fractions.
