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If the supplement of angle Y is 75 then what is the measure of angle Y?
105 degrees
What is the measure of an angle whose supplement is three times its measure?
let x = measure of the mystery angle and y = measure of its supplement By definition of supplement, x+y = 180 since any angle and its supplement sum to a straight angle The problem gives us that 3x = y Substituting in 3x for y in the supplement equation gives us x + 3x = 180 4x = 180 x = 180/4 x = 45 Check our answer: The supplement of 45 degrees is 180 - 45 = 135. 45*3 = 135. Therefore, the answer is 45 degrees.
How do you find the side length of a triangle?
The most popular triangle used in construction, engineering and mathematics is the right triangle, which has a 90o angle at the base. We'll call your base "x", height "y" and diagonal (hypotenuse) "r".You can find these values using your calculator's trigonometric functions, or you can use the Pythagorean Theorem.Finding Values (Pythagorean Theorem):The Pythagorean Theorem is straightforward and states that, for a right triangle, r^2 = x^2 + y^2. We can use a little bit of algebra to find x, y and r.r = sqrt(x^2 + y^2)r^2 = x^2 + y^2r = sqrt(x^2 + y^2); remove the ^2 from rx = sqrt(r^2 - y^2)r^2 = x^2 + y^2r^2 - y^2 = x^2; move y^2 to the left side of the equationsqrt(r^2 - y^2) = x; remove the ^2 from xy = sqrt(r^2 - x^2)r^2 = x^2 + y^2r^2 - x^2 = y^2; move x^2 to the left side of the equationsqrt(r^2 - x^2) = y; remove the ^2 from yFinding Values (Trigonometric Functions):Acquiring Ratios:cos(angle) = x/rsin(angle) = y/rtan(angle) = y/xAcquiring Angles:cos-1(x/r) = anglesin-1(y/r) = angletan-1(y/x) = angleThat looks confusing. What are cos, sin, tan, etc?They're functions. You give a function input and it outputs something else. How they do this is complicated and required calculus.x = cos(angle) * rcos(angle) = x/rcos(angle) * r = x; move r to the left side of the equationy = sin(angle) * rsin(angle) = y/rsin(angle) * r = y; move r to the left side of the equationx = 1 / (tan(angle)/y)tan(angle) = y/xtan(angle) / y = 1/x; move y to the left side of the equation1 / (tan(angle) / y) = x; flip the equationy = tan(angle) * xtan(angle) = y/xtan(angle) * x = y; move x to the left side of the equationr = 1 / (cos(angle)/x)cos(angle) = x/rcos(angle) / x = 1/r; move x to the left side of the equation1 / (cos(angle)/x) = r; flip the equationr = 1 / (sin(angle)/y)sin(angle) = y/rsin(angle) / y = 1/r; move y to the left side of the equation1 / (sin(angle)/y) = r; flip the equation
Angle abc is congruent to angle def Angle A is 22 degrees Angle D is 5y-3 degrees Find x y Given are the hypotenuse of 9 and 3x?
Angle_abc_is_congruent_to_angle_def_Angle_A_is_22_degrees_Angle_D_is_5y-3_degrees_Find_x_y_Given_are_the_hypotenuse_of_9_and_3x
How do you find resultant of forces along sides of regular hexagon?
simply by finding the component y and x along these sides with an angle of 60 degree (notice the forces are outer the hexagon) then using the square root of the sum of the individual squared y and xand then to find the angle use tan@=(y/x)
